제출 #488864

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
488864		cfalas	밀림 점프 (APIO21_jumps)	C++14	21 / 100	4067 ms	16640 KiB

jumps

#include "jumps.h"
#include<bits/stdc++.h>
using namespace std;
#define mp make_pair
#define INF 10000000
#define MOD 1000000007
#define MID ((l+r)/2)
#define HASHMOD 2305843009213693951
#define ll long long
#define ull unsigned long long
#define F first
#define S second
typedef pair<ll, ll> ii;
typedef pair<ii, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef map<int, int> mii;

#define EPS 1e-6
#define FOR(i,n) for(int i=0;i<((int)(n));i++)
#define FORi(i,a,b) for(int i=((int)(a));i<((int)(b));i++)
#define FOA(v, a) for(auto v : a)

int t, n;
vi a, b;

vi nl, pl;

struct node{
	node* L=NULL, *R=NULL;
	int val=n;

	void update(int x, int v, int l=0, int r=n-1){
		if(l==r && l==x){
			val = v;
			//cout<<l<<" "<<r<<" "<<val<<endl;
		}
		else if(l==r || l>x || r<x) return;
		else{
			if(!L) L = new node();
			if(!R) R = new node();
			val = n;
			L->update(x, v, l, MID), val = min(val, L->val);
			R->update(x,v, MID+1,r), val = min(val, R->val);
			//cout<<l<<" "<<r<<" "<<val<<endl;
		}
	}

	int query(int rl, int rr, int l=0, int r=n-1){
		if(rl<=l && r<=rr) return val;
		else if(rl>r || l>rr) return n;
		else {
			if(!L) L = new node();
			if(!R) R = new node();
			return min(L->query(rl, rr, l, MID), R->query(rl,rr,MID+1,r));
		}
	}
};

node seg;
void init(int N, std::vector<int> H) {
	n = N;
	a.resize(n);
	nl.resize(n);
	FOR(i,n) a[i] = H[i];
	
	FORi(i,1,n+1){
		//cout<<endl;
		nl[n-i] = seg.query(a[n-i], n-1);
		seg.update(a[n-i]-1, n-i);
	}
	//FOR(i,n) cout<<nl[i]<<" ";
	//cout<<endl;
}

int minimum_jumps(int A, int B, int C, int D) {
	queue<int> q;
	vi vis(n+1, false);
	FORi(i,A,B+1) q.push(i), vis[i] = true;
	q.push(-1);
	int ans=0;
	bool f = false;
	while(q.size()>1){
		int t = q.front();
		q.pop();
		if(t==-1){
			ans++;
			q.push(-1);
			continue;
		}
		if(C<=t && t<=D){
			f = true;
			break;
		}
		if(!vis[nl[t]] && nl[t]<n){
			vis[nl[t]] = true;
			q.push(nl[t]);
		}
		FORi(i,1,t+1){
			if(!vis[t-i] && a[t-i]>a[t]){
				vis[t-i] = true;
				q.push(t-i);
				break;
			}
			else if(a[t-i]>a[t]) break;
		}
	}
	if(f) return ans;
	else return -1;
}

• Subtask 1: 0 / 4
• Subtask 2: 8 / 8
• Subtask 3: 13 / 13
• Subtask 4: 0 / 12
• Subtask 5: 0 / 23
• Subtask 6: 0 / 21
• Subtask 7: 0 / 19