제출 #488717

#제출 시각아이디문제언어결과실행 시간메모리
488717grt벽 (IOI14_wall)C++17
24 / 100
443 ms11660 KiB
#include <bits/stdc++.h> #include <wall.h> #define PB push_back #define ST first #define ND second //#pragma GCC optimize ("O3") //#pragma GCC target("tune=native") //mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> //using namespace __gnu_pbds; //typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; using namespace std; using ll = long long; using pi = pair<int, int>; using vi = vector<int>; const int INF = 1e9; int n, k; struct Node { int h, H; void eval(Node &u) { h = max(h, u.h); if(h > H) H = INF; H = min(H, u.H); if(h > H) h = H; } }; Node T[(1 << 21)]; void prop(int x) { T[2*x].eval(T[x]); T[2*x+1].eval(T[x]); T[x] = {0, INF}; } void init(int l, int r, int v) { T[v].h = 0; T[v].H = INF; if(l == r) return; int mid = (l + r)/2; init(l,mid,v*2); init(mid+1,r,v*2+1); } void tree(int l, int r, int v) { cout << l << " " << r << ": " << T[v].h << " " << T[v].H << "\n"; if(l==r) return; tree(l,(l+r)/2,v*2); tree((l+r)/2+1,r,v*2+1); } void upd(int a, int b, int l, int r, int v, Node u) { if(a <= l && r <= b) { T[v].eval(u); return; } prop(v); int mid = (l + r) / 2; if(a <= mid) upd(a,b,l,mid,v*2,u); if(mid < b) upd(a,b,mid+1,r,v*2+1,u); } int res[2'000'000 + 10]; void rec(int l, int r, int v) { if(l == r) { res[l] = min(T[v].h, T[v].H); return; } prop(v); int mid = (l+r)/2; rec(l,mid,v*2); rec(mid+1,r,v*2+1); } void buildWall(int _n, int _k, int op[], int l[], int r[], int hei[], int ans[]) { n = _n; k = _k; init(0, n-1, 1); for(int i = 0; i < k; ++i) { if(op[i]-1) { upd(l[i], r[i], 0, n-1, 1, {0, hei[i]}); } else { upd(l[i], r[i], 0, n-1, 1, {hei[i], INF}); } //tree(0,n-1,1); //cout << "-----\n"; } rec(0,n-1,1); //tree(0,n-1,1); //cout << "----\n"; for(int i = 0; i < n; ++i) { ans[i] = res[i]; //cout << ans[i] << " "; } } //int main() { //ios_base::sync_with_stdio(0); //cin.tie(0); //cin >> n >> k; //int op[k], l[k], r[k], hei[k], ans[n]; //for(int i = 0; i < k; ++i) { //cin >> op[i] >> l[i] >> r[i] >> hei[i]; //} //buildWall(n,k,op,l,r,hei,ans); //}
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