제출 #488434

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
488434		cfalas	Financial Report (JOI21_financial)	C++14	100 / 100	1770 ms	95108 KiB

Main

#include<bits/stdc++.h>
using namespace std;
#define mp make_pair
#define INF 10000000
#define MOD 1000000007
#define MID ((l+r)/2)
#define HASHMOD 2305843009213693951
#define ll long long
#define ull unsigned long long
#define F first
#define S second
typedef pair<ll, ll> ii;
typedef pair<ii, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef map<int, int> mii;

#define EPS 1e-6
#define FOR(i,n) for(int i=0;i<((int)(n));i++)
#define FORi(i,a,b) for(int i=((int)(a));i<((int)(b));i++)
#define FOA(v, a) for(auto v : a)

vi a, b;
int n, k;
map<int, int> m;

int pos[900000];

struct node{
	node *L, *R;
	int val, p;

	void build(int l=0, int r=n-1){
		if(l==r) val = -MOD, p=l;
		else{
			L = new node();
			R = new node();
			L->build(l,MID);
			R->build(MID+1, r);
			val = -MOD;
			p = L->p;
		}
	}

	void update(int pos, int v, int l=0, int r=n-1){
		if(l==r && l==pos) val = v;
		else if (l==r || pos<l || pos>r) return;
		else{
			L->update(pos,v,l,MID);
			R->update(pos,v,MID+1,r);
			val = max(L->val, R->val);
			if(L->val > R->val) p = L->val;
			else p = R->val;
		}
	}

	int query(int rl, int rr, int l=0, int r=n-1){
		if(rl<=l && r<=rr) return val;
		else if(l>rr || rl>r) return -MOD;
		else return max(L->query(rl,rr,l,MID), R->query(rl,rr,MID+1,r));
	}

	int queryp(int rl, int rr, int l=0, int r=n-1){
		if(rl<=l && r<=rr) return p;
		else if(l>rr || rl>r) return 0;
		else{
			int a1 = L->query(rl,rr,l,MID);
			int a2 = R->query(rl,rr,MID+1,r);
			if(a1>=a2) return L->queryp(rl,rr,l,MID);
			else return R->queryp(rl,rr,MID+1,r);
		}
	}
};

int main(){
	node seg;
	node seg2;
	ios::sync_with_stdio(false);
	cin.tie(0);
	cin>>n>>k;
	seg.build();
	seg2.build();

	a.resize(n);
	FOR(i,n) cin>>a[i];

	int cnt=0;
	set<int> all;
	FOR(i,n) all.insert(a[i]);
	FOA(v, all) m[v] = ++cnt;
	FOR(i,n) a[i] = m[a[i]];
	//FOR(i,n) cout<<a[i]<<" "; cout<<endl;
	FOR(i,n) seg2.update(i, -a[i]);

	node seg3;
	seg3.build();
	FOR(i,n-k+1) seg3.update(i, -seg2.query(i, i+k-1));

	FOR(i,n){
		int l=i+1, r=n-k;
		pos[i] = n-1;
		while(l<=r){
			if(seg3.query(i+1, MID)>a[i]) pos[i] = MID+k-1, r=MID-1;
			else l=MID+1;
		}
		//cout<<pos[i]<<" ";
		/*
		int cnt=0;
		pos[i] = n-1;
		FORi(j,i+1,n){
			if(a[j]>a[i]) cnt++;
			else cnt=0;
			if(cnt<=k && a[j]>a[i]) pos[i] = j;
			if(cnt>=k) break;
		}*/
		//cout<<pos[i]<<endl;
	}
	//cout<<endl;

	vii b(n);
	FOR(i,n) b[i] = {-a[i], i};
	sort(b.begin(), b.end());
	FOA(v,b){
		int ans = seg.query(v.S+1, pos[v.S]);
		ans = max(ans, 0);
		//cout<<v.S+1<<" "<<pos[v.S]<<" "<<ans<<endl;
		seg.update(v.S, 1+ans);
	}
	//cout<<endl;
	cout<<seg.query(0, n-1)<<endl;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 12 / 12
• Subtask 5: 5 / 5
• Subtask 6: 35 / 35