This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define rep(i, a, b) for (int i = (a); i < (b); ++i)
#define per(i, a, b) for (int i = (b - 1); i >= (a); --i)
#define trav(a, x) for (auto &a : x)
#define all(x) x.begin(), x.end()
#define sz(x) x.size()
#define pb push_back
#define debug(x) cout << #x << " = " << x << endl
#define umap unordered_map
#define uset unordered_set
typedef pair<int, int> ii;
typedef pair<int, ii> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<vi> vvi;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<pll> vpll;
const int INF = 1'000'000'007;
string str;
struct Node {
Node *l, *r;
int lo, hi, sum, best, pref, suf;
Node(int L, int R) : lo(L), hi(R) {
if (hi - lo == 1) {
sum = str[lo] == 'C' ? -1 : 1;
best = pref = suf = max(sum, 0);
} else {
int mid = (lo + hi) / 2;
l = new Node(lo, mid);
r = new Node(mid, hi);
best = max(max(l->best + r->sum, l->sum + r->best), l->pref + r->suf);
sum = l->sum + r->sum;
pref = max(l->pref, l->sum + r->pref);
suf = max(r->suf, r->sum + l->suf);
}
}
pair<ii, ii> query(int L, int R) {
if (hi <= L || R <= lo) return {{0, 0}, {0, 0}};
if (L <= lo && hi <= R) return {{sum, best}, {pref, suf}};
int lsum, lbest, lpref, lsuf;
auto val = l->query(L, R);
tie(lsum, lbest) = val.first;
tie(lpref, lsuf) = val.second;
int rsum, rbest, rpref, rsuf;
val = r->query(L, R);
tie(rsum, rbest) = val.first;
tie(rpref, rsuf) = val.second;
int cur_best = max(max(lbest + rsum, lsum + rbest), lpref + rsuf);
int cur_sum = lsum + rsum;
int cur_pref = max(lpref, lsum + rpref);
int cur_suf = max(rsuf, rsum + lsuf);
return {{cur_sum, cur_best}, {cur_pref, cur_suf}};
}
};
int main() {
cin.tie(0)->sync_with_stdio(0);
cin.exceptions(cin.failbit);
int n, q;
cin >> n >> str >> q;
Node segtree(0, n);
while (q--) {
int lo, hi;
cin >> lo >> hi;
auto val = segtree.query(lo - 1, hi);
int best = val.first.second, pref, suf;
tie(pref, suf) = val.second;
cout << max(best,max(pref,suf)) << endl;
}
return 0;
}
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