#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int mxN = 2e5 + 5, mod = 1e9 + 7, LOG = 20;
int n, a[mxN];
ll p[mxN], res[mxN];
pair <ll, int> dp[mxN];
int main() {
ios :: sync_with_stdio(false), cin.tie(nullptr);
cin >> n;
for (int i = 1; i <= n; ++i) cin >> a[i];
dp[1] = {a[1], 1};
for (int i = 2; i <= n; ++i) {
if (dp[i - 1].first >= dp[i - 2].first + a[i]) {
p[i] = dp[i - 1].second;
dp[i] = dp[i - 1];
}
else {
p[i] = dp[i - 2].second;
dp[i] = {dp[i - 2].first + a[i], i};
}
}
int now = dp[n].second;
multiset <int> lmao;
ll ans = 0;
while (now) {
ans += a[now];
lmao.insert(a[now]);
now = p[now];
}
if (n & 1) {
if ((int)lmao.size() < (n + 1) / 2) {
ll bruh = 0;
for (int i = 1; i <= n; i += 2) bruh += a[i];
res[(n + 1) / 2] = bruh;
for (int i = n / 2; i > 0; i--) {
res[i] = ans;
ans -= *lmao.begin();
lmao.erase(lmao.begin());
}
for (int i = 1; i <= (n + 1) / 2; ++i) cout << res[i] << '\n';
return 0;
}
}
for (int i = (n + 1) / 2; i > 0; i--) {
res[i] = ans;
ans -= *lmao.begin();
lmao.erase(lmao.begin());
}
for (int i = 1; i <= (n + 1) / 2; ++i) cout << res[i] << '\n';
return 0;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
5067 ms |
460 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
5067 ms |
460 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |