제출 #486104

#제출 시각아이디문제언어결과실행 시간메모리
486104Duy_eRabbit Carrot (LMIO19_triusis)C++14
63 / 100
1082 ms3820 KiB
#include <bits/stdc++.h>
#define ll long long
#define ull unsigned long long
#define pii pair<long long, long long>
#define st first
#define nd second
#define file "test"
using namespace std;
const long long oo = 1e18;
const long long N = 2e5 + 5;

ll n, m, h[N], dp[N];

int main()
{
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    // #ifndef ONLINE_JUDGE
    //     freopen(file".inp","r",stdin); freopen(file".out","w",stdout);
    // #endif
    
    cin >> n >> m;
    for (int i = 1; i <= n; i ++)
        cin >> h[i];

    for (int i = 0; i <= n + 1; i ++)
        dp[i] = oo;

    dp[0] = 0;
    for (int i = 0; i <= n; i ++){
        for (int j = i + 1; j <= n + 1; j ++)
            if (h[j] <= h[i])
                dp[j] = min(dp[j], dp[i] + j - i - 1);
            else
                if (h[i] + (j - i)*m >= h[j])
                    dp[j] = min(dp[j], dp[i] + j - i - 1);
        // cout << dp[i] << ' ';
    }

    cout << dp[n + 1];
    

    return 0;
}    
/**  /\_/\
    (= ._.)
    / >0  \>1 
  ________________________
 / Brainstorming section /
/=======================/
---
===
with two fixed point i, j you are allowed to change every pole between i, j
-> could it be changed so that you can go from i->j
possible case: 
+ a[j] <= a[i]
+ a[j] - a[i] / m <= j - i + 1








===
**/
// Before submit: spot the visible bug by reading the code. 
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