/**
* author: chowgz
* created: 07/11/2021 15:53:01
**/
#include <bits/stdc++.h>
using namespace std;
int n, p, q;
const int MAXN = 2'000;
int arr[MAXN + 5];
int dp[MAXN + 5][MAXN + 5];
// I looked at the solution. Let dp[i][j] store index covered with
// i short and j long left.
int nxt1[MAXN + 5], nxt2[MAXN + 5];
bool bs(int x) {
for (int i = 0; i < n; i++) {
nxt1[i] = upper_bound(arr, arr + n, arr[i] + x - 1) - arr;
nxt2[i] = upper_bound(arr, arr + n, arr[i] + 2 * x - 1) - arr;
}
nxt1[n] = n;
nxt2[n] = n;
for (int i = p; i >= 0; i--) {
for (int j = q; j >= 0; j--) {
if (i == p) {
if (j == q) {
dp[i][j] = 0;
} else {
dp[i][j] = nxt2[dp[i][j + 1]];
}
} else {
if (j == q) {
dp[i][j] = nxt1[dp[i + 1][j]];
} else {
dp[i][j] = max(nxt1[dp[i + 1][j]], nxt2[dp[i][j + 1]]);
}
}
}
}
return dp[0][0] == n;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> p >> q;
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
int l = 1, r = 1'000'000'000, m;
while (l != r) {
m = (l + r) / 2;
if (bs(m)) {
r = m;
} else {
l = m + 1;
}
}
cout << l << '\n';
return 0;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
0 ms |
204 KB |
Output is correct |
2 |
Correct |
0 ms |
204 KB |
Output is correct |
3 |
Correct |
0 ms |
332 KB |
Output is correct |
4 |
Runtime error |
1 ms |
460 KB |
Execution killed with signal 11 |
5 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
4 ms |
348 KB |
Output is correct |
2 |
Correct |
1 ms |
332 KB |
Output is correct |
3 |
Correct |
371 ms |
12100 KB |
Output is correct |
4 |
Runtime error |
1 ms |
460 KB |
Execution killed with signal 11 |
5 |
Halted |
0 ms |
0 KB |
- |