이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "brperm.h"
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
#define pii pair<int,int>
#define vi vector<int>
#define fi first
#define se second
#define pb push_back
#define ALL(x) x.begin(),x.end()
#define ll long long
using namespace std;
inline ll read(){
ll x=0,f=1;char ch=getchar();
while (!isdigit(ch)){if (ch=='-') f=-1;ch=getchar();}
while (isdigit(ch)){x=x*10+ch-48;ch=getchar();}
return x*f;
}
const int N=5e5+5,P=1e9+7,B=131;
int f[N][20],g[N][20],base[20],b[N][20],t[N],n;
int mul(int a,int b){return 1ll*a*b%P;}
int add(int a,int b){return a+b>P?a+b-P:a+b;}
int sub(int a,int b){return a-b<0?a-b+P:a-b;}
void init(int m,const char s[]){
n=m;
base[19]=B;
per(i,19,1)base[i-1]=mul(base[i],base[i]);
rep(i,0,19){
b[0][i]=1;
rep(j,0,n-1)b[j][i]=mul(b[j-1][i],base[i]);
}
rep(i,0,19){
t[0]=s[0]-'a'+1;
rep(j,1,n-1)t[j]=add(s[i]-'a',mul(t[j-1],base[i]));
f[0][i]=t[(1<<i)-1];
rep(j,1,n-(1<<i)){
f[j][i]=sub(t[j+(1<<i)-1],mul(t[j-1],b[1<<i][i]));
}
}
rep(i,0,n-1)g[i][0]=s[i]-'a'+1;
rep(j,1,19)rep(i,1,n-(1<<j)){
g[i][j]=add(mul(g[i][j-1],base[j]),g[i+(1<<j)][j-1]);
}
}
int query(int i,int k){return i+(1<<k)<=n&&f[i][k]==g[i][k];}
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