제출 #485166

#제출 시각아이디문제언어결과실행 시간메모리
485166kshitij_sodaniSažetak (COCI17_sazetak)C++14
96 / 160
1092 ms204 KiB
//#pragma GCC optimize("Ofast,unroll-loops") #include <bits/stdc++.h> using namespace std; typedef long long llo; #define mp make_pair #define pb push_back #define a first #define b second #define endl '\n' llo n; llo it[11]; #include <iostream> using namespace std; // Function for extended Euclidean Algorithm llo gcdExtended(llo a, llo b, llo* x, llo* y); // Function to find modulo inverse of a llo modInverse(llo a, llo m) { //cout << "Inverse doesn't exist"; llo x, y; llo g = gcdExtended(a, m, &x, &y); if (g != 1){ return -1; } else { // m is added to handle negative x llo res = (x % m + m) % m; return res; cout << "Modular multiplicative inverse is " << res; } } // Function for extended Euclidean Algorithm llo gcdExtended(llo a, llo b, llo* x, llo* y) { // Base Case if (a == 0) { *x = 0, *y = 1; return b; } // To store results of recursive call llo x1, y1; llo gcd = gcdExtended(b % a, a, &x1, &y1); // Update x and y using results of recursive // call *x = y1 - (b / a) * x1; *y = x1; return gcd; } int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); cin>>n; llo k; cin>>k; for(llo i=0;i<k;i++){ cin>>it[i]; } llo ans=0; for(llo i=n;i<=n;i++){ llo st=0; llo st2=0; if(i==n){ st=1; } for(llo j=0;j<k;j++){ llo x=i%it[j]; if(x==0){ st=1; } else if(x==1){ st2=1; } } if(st==1 and st2==1){ ans++; } } n--; for(llo i=1;i<(1<<k);i++){ llo x=0; llo zz=-1; vector<llo> ss; for(llo j=0;j<k;j++){ if((1<<j)&i){ zz=-zz; if(x==0){ x=it[j]; } else{ x=(x*it[j])/__gcd(x,it[j]); } } else{ ss.pb(j); } } llo co=0; llo x2=ss.size(); for(llo j=1;j<(1<<x2);j++){ llo xx=0; llo st=-1; for(llo jj=0;jj<x2;jj++){ if((1<<jj)&j){ st=-st; if(xx==0){ xx=it[ss[jj]]; } else{ xx=(xx*it[ss[jj]])/(__gcd(xx,it[ss[jj]])); } } } //cout<<i<<":"<<j<<":"<<x<<":"<<xx<<endl; if(__gcd(xx,x)>1){ continue; } //cout<<i<<":"<<j<<":"<<x<<":"<<xx<<endl; llo y=modInverse(x,xx); if(y==-1){ while(true){ continue; } } // cout<<y<<endl; llo nn=n/x; if(y<=nn){ co+=st*(1+(nn-y)/xx); } //co+=st*((n/(y*x))); } ans+=zz*co; } cout<<ans<<endl; return 0; }
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