# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
485165 | kshitij_sodani | Sažetak (COCI17_sazetak) | C++14 | 26 ms | 316 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("Ofast,unroll-loops")
#include <bits/stdc++.h>
using namespace std;
typedef long long llo;
#define mp make_pair
#define pb push_back
#define a first
#define b second
#define endl '\n'
llo n;
llo it[11];
#include <iostream>
using namespace std;
// Function for extended Euclidean Algorithm
llo gcdExtended(llo a, llo b, llo* x, llo* y);
// Function to find modulo inverse of a
llo modInverse(llo a, llo m)
{ //cout << "Inverse doesn't exist";
llo x, y;
llo g = gcdExtended(a, m, &x, &y);
if (g != 1){
return -1;
}
else
{
// m is added to handle negative x
llo res = (x % m + m) % m;
return res;
cout << "Modular multiplicative inverse is " << res;
}
}
// Function for extended Euclidean Algorithm
llo gcdExtended(llo a, llo b, llo* x, llo* y)
{
// Base Case
if (a == 0)
{
*x = 0, *y = 1;
return b;
}
// To store results of recursive call
llo x1, y1;
llo gcd = gcdExtended(b % a, a, &x1, &y1);
// Update x and y using results of recursive
// call
*x = y1 - (b / a) * x1;
*y = x1;
return gcd;
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin>>n;
llo k;
cin>>k;
for(llo i=0;i<k;i++){
cin>>it[i];
}
llo ans=0;
for(llo i=n;i<=n;i++){
llo st=0;
llo st2=0;
if(i==n){
st=1;
}
for(llo j=0;j<k;j++){
llo x=i%it[j];
if(x==0){
st=1;
}
else if(x==1){
st2=1;
}
}
if(st==1 and st2==1){
ans++;
}
}
n--;
for(llo i=1;i<(1<<k);i++){
llo x=0;
llo zz=-1;
vector<llo> ss;
for(llo j=0;j<k;j++){
if((1<<j)&i){
zz=-zz;
if(x==0){
x=it[j];
}
else{
x=(x*it[j])/__gcd(x,it[j]);
}
}
else{
ss.pb(j);
}
}
llo co=0;
llo x2=ss.size();
for(llo j=1;j<(1<<x2);j++){
llo xx=0;
llo st=-1;
for(llo jj=0;jj<x2;jj++){
if((1<<jj)&j){
st=-st;
if(xx==0){
xx=it[ss[jj]];
}
else{
xx=(xx*it[ss[jj]])/(__gcd(xx,it[ss[jj]]));
}
}
}
//cout<<i<<":"<<j<<":"<<x<<":"<<xx<<endl;
if(__gcd(xx,x)>1){
continue;
}
//cout<<i<<":"<<j<<":"<<x<<":"<<xx<<endl;
llo y=modInverse(x,xx);
// cout<<y<<endl;
llo nn=n/x;
if(y<=nn){
co+=st*(1+(nn-y)/xx);
}
//co+=st*((n/(y*x)));
}
ans+=zz*co;
}
cout<<ans<<endl;
return 0;
}
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