제출 #485068

#제출 시각아이디문제언어결과실행 시간메모리
485068CSQ31Bitaro’s Party (JOI18_bitaro)C++17
100 / 100
1251 ms419908 KiB
#include<bits/stdc++.h> using namespace std; #define pb push_back #define fi first #define se second #define sz(a) (int)(a.size()) #define all(a) a.begin(),a.end() #define lb lower_bound #define ub upper_bound #define owo ios_base::sync_with_stdio(0);cin.tie(0); #define MOD (ll)(1e9+7) #define INF (ll)(1e18) #define debug(...) fprintf(stderr, __VA_ARGS__),fflush(stderr) #define time__(d) for(long blockTime = 0; (blockTime == 0 ? (blockTime=clock()) != 0 : false);\ debug("%s time : %.4fs\n", d, (double)(clock() - blockTime) / CLOCKS_PER_SEC)) typedef long long int ll; typedef long double ld; typedef pair<ll,ll> PII; typedef pair<int,int> pii; typedef vector<vector<int>> vii; typedef vector<vector<ll>> VII; ll gcd(ll a,ll b){if(!b)return a;else return gcd(b,a%b);} const int sq = 350,MAXN = 1e5+1; bool take[MAXN],vis[MAXN]; int dp[MAXN]; vector<int>adj[MAXN],radj[MAXN]; vector<pii>good[MAXN]; int main() { owo int n,m,q; cin>>n>>m>>q; for(int i=0;i<m;i++){ int v,u; cin>>v>>u; adj[v].pb(u); radj[u].pb(v); } //good[i] stores the sq longest paths to i //in decreasing order for(int i=1;i<=n;i++){ for(int x:radj[i]){ vector<pii>fin; good[x].pb({0,x}); //duplicates are dangerous int a = 0,b=0; int sa = sz(good[x]); int sb = sz(good[i]); while(sz(fin)<sq && (a<sa || b < sb)){ if(b == sb || (a!=sa && good[x][a].fi+1 >= good[i][b].fi)){ good[x][a].fi++; fin.pb(good[x][a]); vis[good[x][a].se] = 1; good[x][a].fi--; a++; }else{ fin.pb(good[i][b]); vis[good[i][b].se] = 1; b++; } while(a<sa && vis[good[x][a].se])a++; while(b<sb && vis[good[i][b].se])b++; } good[x].pop_back(); for(auto z:fin)vis[z.se] = 0; swap(good[i],fin); } } cout<<'\n'; while(q--){ int t,y; cin>>t>>y; vector<int>c(y); for(int i=0;i<y;i++){ cin>>c[i]; take[c[i]] = 1; } int ans = -1; if(y>=350){ //this should be correct for(int i=1;i<=n;i++)dp[i] = -1; dp[t] = 0; if(!take[t])ans = 0; for(int i=t-1;i;i--){ for(int x:adj[i]){ if(dp[x]!=-1)dp[i] = max(dp[i],dp[x]+1); } if(!take[i])ans = max(ans,dp[i]); } }else{ for(auto x:good[t]){ if(!take[x.se]){ ans = x.fi; break; } } if(!take[t])ans = max(ans,0); } cout<<ans<<'\n'; for(int i=0;i<y;i++)take[c[i]] = 0; } }
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