제출 #484769

#제출 시각아이디문제언어결과실행 시간메모리
484769BackNoobRobot (JOI21_ho_t4)C++14
34 / 100
3083 ms142072 KiB
#include <bits/stdc++.h> #define ll long long #define fi first #define se second #define endl '\n' #define MASK(i) (1LL << (i)) #define ull unsigned long long #define ld long double #define pb push_back #define all(x) (x).begin() , (x).end() #define BIT(x , i) ((x >> (i)) & 1) #define TASK "task" #define sz(s) (int) (s).size() using namespace std; const int mxN = 3e5 + 227; const int inf = 1e9 + 277; const int mod = 1e9 + 7; const ll infll = 1e18 + 7; const int base = 307; const int LOG = 20; template <typename T1, typename T2> bool minimize(T1 &a, T2 b) { if (a > b) {a = b; return true;} return false; } template <typename T1, typename T2> bool maximize(T1 &a, T2 b) { if (a < b) {a = b; return true;} return false; } struct item{ int u; int pre; ll d; }; struct cmp{ bool operator()(const item &a , const item &b) { return a.d > b.d; } }; struct EDGE{ int v , color , cost; }; int n , m; vector<EDGE> adj[mxN]; ll dist[mxN]; unordered_map<int , ll> dp[mxN]; int cnt[mxN]; unordered_map<int , ll> sumcost[mxN]; unordered_map<int , vector<pair<int , int>>> adjcolor[mxN]; void solve() { cin >> n >> m; for(int i = 1 ; i <= m ; i++) { int u , v , color , cost; cin >> u >> v >> color >> cost; adj[u].pb({v , color , cost}); adj[v].pb({u , color , cost}); adjcolor[u][color].pb({v , cost}); adjcolor[v][color].pb({u , cost}); sumcost[u][color] += cost; sumcost[v][color] += cost; } memset(dist , 0x3f , sizeof(dist)); priority_queue <tuple <ll, int, int>, vector <tuple <ll, int, int>>, greater <tuple <ll, int, int>>> pq; pq.push({dist[1] = 0 , 1 , 0}); while(!pq.empty()) { int u , pre; ll d; tie(d , u , pre) = pq.top(); pq.pop(); if(pre == 0 && dist[u] != d) continue; if(pre == 0) { for(auto it : adj[u]) { if(!dp[it.v].count(u) || dp[it.v][it.color] > d) { dp[it.v][it.color] = d; pq.push({d , it.v , it.color}); } if(minimize(dist[it.v] , d + sumcost[u][it.color] - it.cost) == true) { pq.push({d + sumcost[u][it.color] - it.cost , it.v , 0}); } if(minimize(dist[it.v] , d + it.cost) == true) { pq.push({d + it.cost , it.v , 0}); } } } if(pre != 0) { if(pre != 0 && dp[u][pre] != d) continue; for(auto it : adjcolor[u][pre]) { if(minimize(dist[it.fi] , d + sumcost[u][pre] - it.se) == true) { pq.push({d + sumcost[u][pre] - it.se , it.fi , 0}); } } } } ll ans = dist[n]; if(ans == dist[0]) cout << -1; else cout << ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(0); //freopen(TASK".inp" , "r" , stdin); //freopen(TASK".out" , "w" , stdout); int tc = 1; //cin >> tc; while(tc--) { solve(); } return 0; }
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