이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<ll, int> pli;
typedef pair<int, ll> pil;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<pli> vli;
typedef vector<pil> vil;
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
const int MOD = 1000000007; // 998244353
const ll INF = 1e18;
const int oo = 1000000007;
const int MX = 100001;
const ld PI = 4 * atan((ld)1);
int n, s;
vi v, w, t;
void solve() {
cin >> s >> n;
v.resize(n + 1); w.resize(n + 1); t.resize(n + 1);
for (int i = 1; i <= n; i++) cin >> v[i] >> w[i] >> t[i];
vector<vi> dp(n + 1, vi(s + 1, 0));
dp[0][0] = 1;
for (int i = 0; i < n; i++) for (int j = 0; j <= s; j++) {
dp[i + 1][j] = dp[i][j];
if (j - w[i + 1] >= 0) dp[i + 1][j] = max(dp[i + 1][j], dp[i][j - w[i + 1]] + v[i + 1]);
}
cout << dp[n][s];
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL); cout.tie(NULL);
solve();
return 0;
}
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