# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
484508 | Carmel_Ab1 | 크레이피쉬 글쓰는 기계 (IOI12_scrivener) | C++17 | 0 ms | 0 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//using namespace __gnu_pbds;
using namespace std;
typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef vector<int> vi;
typedef vector<vector<int>> vvi;
typedef vector<ll> vl;
typedef vector<vl> vvl;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef vector<pl> vpl;
typedef vector<ld> vld;
typedef pair<ld, ld> pld;
typedef vector<pi> vpi;
//typedef tree<ll, null_type, less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
template<typename T>
ostream &operator<<(ostream &os, vector<T> &a) {
os << "[";
for (int i = 0; i < ll(a.size()); i++) { os << a[i] << ((i != ll(a.size() - 1) ? " " : "")); }
os << "]\n";
return os;
}
#define all(x) x.begin(),x.end()
#define YES out("YES")
#define NO out("NO")
#define out(x){cout << x << "\n"; return;}
#define GLHF ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL)
#define print(x){for(auto ait:x) cout << ait << " "; cout << "\n";}
#define pb push_back
#define umap unordered_map
template<typename T1, typename T2>
istream &operator>>(istream &is, pair<T1, T2> &p) {
is >> p.first >> p.second;
return is;
}
template<typename T1, typename T2>
ostream &operator<<(ostream &os, pair<T1, T2> &p) {
os << "" << p.first << " " << p.second << "";
return os;
}
void usaco(string taskname) {
string fin = taskname + ".in";
string fout = taskname + ".out";
const char *FIN = fin.c_str();
const char *FOUT = fout.c_str();
freopen(FIN, "r", stdin);
freopen(FOUT, "w", stdout);
}
template<typename T>
void read(vector<T> &v) {
int n = v.size();
for (int i = 0; i < n; i++)
cin >> v[i];
}
template<typename T>
vector<T> UNQ(vector<T> a) {
vector<T> ans;
for (T t: a)
if (ans.empty() || t != ans.back())
ans.push_back(t);
return ans;
}
ll ceil(ll a, ll b) {
ll ans = a / b;
if (a % b)ans++;
return ans;
}
ld log(ld a, ld b) { return log(b) / log(a); }
ll power(ll base, ll exp, ll M = 1e18) {//(base^exp)%M
ll ans = 1;
while (exp) {
if (exp % 2 == 1)ans = ((ans % M) * (base % M)) % M;
base = ((base % M) * (base % M)) % M;
exp /= 2;
}
return ans;
}
string to_base(int n, int new_base) {
string s;
int nn = n;
while (nn) {
s += to_string(nn % new_base);
nn /= new_base;
}
reverse(all(s));
return s;
}
ll gcd(ll a, ll b) {
if (a < b)swap(a, b);
if (b == 0)return a;
return gcd(b, a % b);
}
ll lcm(ll a, ll b) {
ll x = (a / gcd(a, b));
return b * x;
}
vl generate_array(ll n, ll mn = 1, ll mx = 1e18 + 1) {
if (mx == 1e18 + 1)
mx = n;
vl ans(n);
for (int i = 0; i < n; i++)
ans[i] = (mn + rand() % (mx - mn + 1));
return ans;
}
string substr(string s, int l, int r) {
string ans;
for (int i = l; i <= r; i++)
ans += s[i];
return ans;
}
void solve();
int main() {
GLHF;
int t = 1;
//cin >> t;
while (t--)
solve();
}
string s;
vi prv,sz;
int timer=0;
vvi dp;
int lst=-1;
void add_row(){
int cur=timer-1;
if(s[cur]==' ')
dp[cur][0]=dp[prv[cur]][0];
else
dp[cur][0]=(cur?prv[cur-1]:-1);
for(int j=1; j<20; j++)
if(dp[cur][j-1]!=-1)
dp[cur][j]=dp[dp[cur][j-1]][j-1];
}
void T(char c){
s+=c;
prv.pb(timer);
sz.pb(sz.empty()?1:sz.back()+1);
timer++;
add_row();
lst=timer-1;
}
void U(int x){
prv.pb(prv[timer-x-1]);
sz.pb(sz[timer-x-1]);
timer++;
s+=' ';
add_row();
}
string t;
void make_t(){
t="";
int cur=timer-1;
while(0<=cur){
if(s[cur]!=' ')
t+=s[cur];
if(cur==prv[cur])
cur--;
else
cur=prv[cur];
}
reverse(all(t));
}
int query(int x,int k){
for(int i=0; i<20; i++)
if(k&(1<<i))
x=dp[x][i];
return x;
}
int P(int x){
int t=prv[timer-1];
int l=sz[t];
return s[query(t,l-x-1)];
}
void solve() {
int n;
cin >> n;
dp.resize(n,vi(20,-1));
while(n--){
char op;
cin >> op;
if(op=='T'){
char c;
cin >> c;
T(c);
}
else if(op=='U'){
int x;
cin >> x;
U(x);
}
else{
int x;
cin >> x;
cout << char(P(x)) <<"\n";
}
}
out("")
}
/*
6
T a
T b
U 1
T c
U 3
P 0
*/