제출 #483360

#제출 시각아이디문제언어결과실행 시간메모리
483360BERNARB01Global Warming (CEOI18_glo)C++17
62 / 100
495 ms38572 KiB
#include <bits/stdc++.h> using namespace std; template<typename T = int> struct Max { T val; const T nut = 0; Max() { val = nut; } Max(const T& _val) { val = _val; } void operator =(const Max& o) { val = o.val; } Max operator +(const Max& o) const { return val > o.val ? *this : o; } }; template<typename T, typename T2 = int> struct segtree { int b; vector<T> tr; segtree() {} segtree(int n) { b = 1; while (b < n) { b <<= 1; } tr.assign(b << 1, T()); } segtree(const vector<T2>& arr) { b = 1; while (b < (int) arr.size()) { b <<= 1; } tr.assign(b << 1, T()); for (int i = 0; i < (int) arr.size(); i++) { tr[i + b] = T(arr[i]); } bld(); } void bld() { for (int i = b - 1; i > 0; i--) { tr[i] = tr[i << 1] + tr[i << 1 | 1]; } } void upd(int i, const T2& val, bool add = false) { i += b; tr[i] = (add ? tr[i] + T(val) : T(val)); for (i >>= 1; i > 0; i >>= 1) { tr[i] = tr[i << 1] + tr[i << 1 | 1]; } } T qry(int l, int r) { T ansl = T(), ansr = T(); for (l += b, r += b; l <= r; l >>= 1, r >>= 1) { if (l & 1) ansl = ansl + tr[l++]; if (!(r & 1)) ansr = tr[r--] + ansr; } return ansl + ansr; } int idx_of_last_max() { int ret = 0; for (int i = 2; i < 2 * b; i <<= 1) { i += (tr[i + 1].val == tr[1].val); ret = i - b; } return ret; } }; int main() { ios::sync_with_stdio(false); cin.tie(0); int n, x; cin >> n >> x; vector<int> a(n); map<int, int> mp; for (int i = 0; i < n; i++) { cin >> a[i]; mp[a[i]] = 0; mp[a[i] + x] = 0; } int id = 0; for (auto& [f, s] : mp) { s = id++; } vector<int> b(n); for (int i = 0; i < n; i++) { b[i] = mp[a[i] + x]; } segtree<Max<>> st(id); int lds_len = 1; vector<pair<int, int>> suf(n); for (int i = n - 1; i >= 0; i--) { int j = st.qry(b[i] + 1, id).val; st.upd(b[i], j + 1); lds_len = max(lds_len, st.qry(0, id).val); suf[i] = {lds_len, st.idx_of_last_max()}; } for (int i = 0; i < n; i++) { b[i] = mp[a[i]]; } segtree<Max<>> stt(id); int ans = lds_len; for (int i = 0; i < n - 1; i++) { stt.upd(b[i], 1 + stt.qry(0, b[i] - 1).val); auto [sl, ns] = suf[i + 1]; ans = max(ans, stt.qry(0, ns - 1).val + sl); } cout << ans << '\n'; return 0; }
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