이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#ifdef LOCAL
#include "local.h"
#else
#include <bits/stdc++.h>
#define debug(...)
#define DB(...)
#endif
using namespace std;
const bool __initialization = []() {
cin.tie(nullptr)->sync_with_stdio(false);
cout << setprecision(12) << fixed;
return true;
}();
using ll = long long;
using ld = long double;
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define For(i, l, r) for (int i = (l); i <= (r); ++i)
#define Ford(i, r, l) for (int i = (r); i >= (l); --i)
#define Rep(i, n) For (i, 0, (n) - 1)
#define Repd(i, n) Ford (i, (n) - 1, 0)
#define Fe(...) for (auto __VA_ARGS__)
template <class C> inline int isz(const C& c) { return static_cast<int>(c.size()); }
template <class T> inline bool chmin(T& a, const T& b) { return (a > b) ? a = b, true : false; }
template <class T> inline bool chmax(T& a, const T& b) { return (a < b) ? a = b, true : false; }
constexpr ld eps = 1e-9;
constexpr int inf = 1e9;
constexpr ll linf = 1e18;
// =============================================================================
constexpr int maxn = 1e5 + 5;
#include "ricehub.h"
int n, len;
ll budget;
int a[maxn];
ll pref[maxn];
int check(int L, int R) {
int M = (L + R) / 2;
ll left = 1LL * a[M] * (M - L) - (pref[M - 1] - pref[L - 1]);
ll right = (pref[R] - pref[M]) - 1LL * a[M] * (R - M);
return left + right;
}
int besthub(int _R, int _L, int _X[], ll _B) {
// globalization
n = _R; len = _L; budget = _B;
For (i, 1, n) a[i] = _X[i - 1];
// end of globalization
For (i, 1, n) {
pref[i] = pref[i - 1] + a[i];
}
int ans = 0;
int R = 1;
For (L, 1, n) {
while (R < n && check(L, R + 1) <= budget) {
++R;
}
chmax(ans, R - L + 1);
}
assert(ans != -1);
return ans;
}
// wait this could still get TLE...
// and I'm not even sure if this will be correct...
// iirc this IOI was offline
// bro wtf lmaooooooo
// it worked
// but many people in the actual contest got this correct as well...
// maybe sliding window?
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