제출 #482696

#제출 시각아이디문제언어결과실행 시간메모리
482696jalsolOdašiljači (COCI20_odasiljaci)C++17
70 / 70
83 ms15972 KiB
#ifdef LOCAL #include "local.h" #else #include <bits/stdc++.h> #define debug(...) #define DB(...) #endif using namespace std; const bool __initialization = []() { cin.tie(nullptr)->sync_with_stdio(false); #define TASK "ANGTEN" if (fopen(TASK".inp", "r")) { (void)(!freopen(TASK".inp", "r", stdin)); (void)(!freopen(TASK".out", "w", stdout)); } cout << setprecision(12) << fixed; return true; }(); using ll = long long; using ld = long double; #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define For(i, l, r) for (int i = (l); i <= (r); ++i) #define Ford(i, r, l) for (int i = (r); i >= (l); --i) #define Rep(i, n) For (i, 0, (n) - 1) #define Repd(i, n) Ford (i, (n) - 1, 0) #define Fe(...) for (auto __VA_ARGS__) template <class C> inline int isz(const C& c) { return static_cast<int>(c.size()); } template <class T> inline bool chmin(T& a, const T& b) { return (a > b) ? a = b, true : false; } template <class T> inline bool chmax(T& a, const T& b) { return (a < b) ? a = b, true : false; } constexpr ld eps = 1e-9; constexpr int inf = 1e9; constexpr ll linf = 1e18; // ============================================================================= constexpr int maxn = 1000 + 5; struct Pt { int x, y; }; struct Edge { int u, v; ld c; bool operator<(const Edge& o) const { return c < o.c; } }; int n; Pt a[maxn]; Edge e[maxn * maxn]; int ptr; int par[maxn]; int find(int x) { return (par[x] < 0) ? x : (par[x] = find(par[x])); } bool merge(int u, int v) { u = find(u); v = find(v); if (u == v) return false; if (par[v] < par[u]) swap(u, v); par[u] += par[v]; par[v] = u; return true; } ll sqr(ll x) { return x * x; } ld calc(int i, int j) { return sqrt(sqr(a[i].x - a[j].x) + sqr(a[i].y - a[j].y)); } signed main() { cin >> n; For (i, 1, n) cin >> a[i].x >> a[i].y; For (i, 1, n - 1) { For (j, i + 1, n ) { e[ptr++] = {i, j, calc(i, j)}; } } sort(e, e + ptr); memset(par + 1, -1, sizeof(int) * n); ld ans = 0; Rep (i, ptr) { if (merge(e[i].u, e[i].v)) { ans = e[i].c; } } cout << ans / 2 << '\n'; }
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