Submission #482340

#TimeUsernameProblemLanguageResultExecution timeMemory
482340Blistering_BarnaclesGlobal Warming (CEOI18_glo)C++11
48 / 100
1503 ms157060 KiB
//apig's property //Happiness can be found, even in the darkest of times, if one only remembers to turn on the light //El Pueblo Unido Jamas Sera Vencido //Do or do not... there is no try //Billions of bilious blue blistering barnacles in a thundering typhoon! #include<bits/stdc++.h> #define fast ios_base::sync_with_stdio(0) , cin.tie(0) , cout.tie(0) #define F first #define S second #define pb push_back #define vll vector< ll > #define vi vector< int > #define pll pair< ll , ll > #define pi pair< int , int > #define all(s) s.begin() , s.end() #define sz(s) s.size() #define str string #define md ((s + e) / 2) #define mid ((l + r) / 2) #define msdp(dp) memset(dp , -1 , sizeof dp) #define mscl(dp) memset(dp , 0 , sizeof dp) #define C continue #define R return #define B break #define lx node * 2 #define rx node * 2 + 1 #define br(o) o ; break #define co(o) o ; continue using namespace std; typedef long long ll; ll q, suf[555555] , dp1[555555] , dp2[555555] ,tree2[1000005], a[555555] , tree1[1000005], k, l, m, n, o, p; map < ll , ll > mp; vll adj[555555]; const ll mod = 1e9+7; str s; void update1(ll s , ll e , ll node , ll idx , ll val){ if(s > idx || e < idx)R ; if(s == e){ tree1[node] = max(tree1[node] , val) ; R ; } update1(s , md , lx , idx , val) , update1(md + 1 , e , rx , idx , val) ; tree1[node] = max(tree1[lx] , tree1[rx]) ; } ll query1(ll s , ll e , ll node , ll l , ll r){ if(s > r || e < l || l > r)R 0 ; if(l <= s && e <= r)R tree1[node] ; R max(query1(md + 1 , e , rx , l , r) , query1(s , md , lx , l , r)) ; } void update2(ll s , ll e , ll node , ll idx , ll val){ if(s > idx || e < idx)R ; if(s == e){ tree2[node] = max(tree2[node] , val) ; R ; } update2(s , md , lx , idx , val) , update2(md + 1 , e , rx , idx , val) ; tree2[node] = max(tree2[lx] , tree2[rx]) ; } ll query2(ll s , ll e , ll node , ll l , ll r){ if(s > r || e < l || l > r)R 0 ; if(l <= s && e <= r)R tree2[node] ; R max(query2(md + 1 , e , rx , l , r) , query2(s , md , lx , l , r)) ; } void solve(){ set < ll > se ; cin >> n >> k ; for(ll i = 1 ; i <= n ; i++){ cin >> a[i] ; se.insert(a[i]) ; if(k == 0)se.insert(a[i] - 1) ; else se.insert(a[i] + k - 1) ; } m = 0 ; for(auto u : se){ mp[u] = ++m ; } ll ans = 0 ; for(ll i = n ; i >= 1 ; i--){ dp2[i] = query2(1 , m , 1 , mp[a[i]] + 1 , m) + 1 ; update2(1 , m , 1 , mp[a[i]] , dp2[i]) ; } for(ll i = 1 ; i <= n ; i++){ dp1[i] = query1(1 , m , 1 , 1 , mp[a[i]] - 1) + 1 ; update1(1 , m , 1 , mp[a[i]] , dp1[i]) ; } mscl(tree1) ; for(ll i = 1 ; i <= n ; i++){ if(k == 0){ assert(mp[a[i]] > mp[a[i] - 1]) ; } ans = max(ans , dp2[i] + query1(1 , m , 1 , mp[a[i]] , mp[a[i] + k - 1])) ; update1(1 , m , 1 , mp[a[i]] , dp1[i]); } cout << ans << endl ; } int main(){ fast ; q = 1 ; //cin >> q ; while(q--){ solve() ; } }
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