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#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
/**
* If you live in imaginary world when your imaginary situation encounter in
* real situation you can't enjoiy it because you have to do pending work.
* {This pending work appeared because you wasted that time for your useless
* imagianry thinking.}
*/
#include<bits/stdc++.h>
using namespace std;
//#define int int64_t
#define all(x) x.begin(),x.end()
#define all1(x) x.rbegin(),x.rend()
#define sz(x) (int)x.size()
const int N=5e5+5;
int dp[2][2001];
vector<pair<int,int>> ok[20001];
void solve(){
int s,n;
cin>>s>>n;
for (int i=0,x,y,z;i<n;i++){
cin>>y>>x>>z;
ok[x].push_back({y,z});
// cin>>ok[i][1]>>ok[i][0]>>ok[i][2];
}
int u(0);
int cur=1,prv=0;
for (int i=1;i<=s;i++){
sort(all(ok[i]));
int req=s/i;
int best=1;
bool cur1=true;
for (int j1=1,f=sz(ok[i])-1;j1<=req && f!=-1;j1++){
u=ok[i][f].first;
if (!cur1){break;}
cur1=true;
for (int j=best;j<=s;j++){
dp[cur][j]=dp[prv][j];
if (j>=i && dp[cur][j]<dp[prv][j-i]+u){
dp[cur][j]=dp[prv][j-i]+u;
if (cur1){best=j;cur1=0;}
}
}
ok[i][f].second--;
if (ok[i][f].second==0){f--;}
swap(cur,prv);
}
}
int ans=0;
prv=n&1;
for (int i=1;i<=s;i++){ans=max(ans,dp[prv][i]);}
cout<<ans;
}
int32_t main(){
ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);
//freopen("feast.in","r",stdin);
//freopen("feast.out","w",stdout);
int tq=1;
//cin>>tq;
for (;tq;tq--){solve();}
}
//is a bruteforce possible?
//think greedier, make more assumptions
// if we you find solution using loop to decrease complexity use bs
//stuck for more than 5 minutes? move on
컴파일 시 표준 에러 (stderr) 메시지
knapsack.cpp:3: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
3 | #pragma GCC optimization ("unroll-loops")
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