# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
479783 | jli12345 | Harbingers (CEOI09_harbingers) | C++14 | 159 ms | 21188 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
void fastIO(){
ios_base::sync_with_stdio(false);
cin.tie(0);
}
typedef long long ll;
#define f first
#define s second
int N;
vector< pair<int, ll> > edges[101000];
pair<ll, ll> city[100100]; // w, t
ll dist[100100], dp[100100];
int convex[100100];
int pos = 0;
ll m(int ind){
return -dist[ind];
}
ll b(int ind){
return dp[ind];
}
ll val(int j, int i){
return m(j)*city[i].s+b(j);
}
ll add(int ind){
return dist[ind]*city[ind].s+city[ind].f;
}
ll best(int node){
if (node == 1) return 0;
int l = 1, r = pos;
while (l != r){
int mid = (l+r+1)/2;
if (val(convex[mid], node) >= val(convex[mid-1], node)){
r = mid-1;
} else {
l = mid;
}
}
/*
if (node == 3)
cout << "best:" << l << " " << val(convex[l], node) << " " << add(node) << "\n";
*/
return val(convex[l], node)+add(node);
}
long double intersect(int aa, int bb){
return (long double)(b(aa)-b(bb))/(m(bb)-m(aa));
}
pair<int, ll> insert(int node){ //returns the index of insertion and previous value at that insertion
if (node == 1){
convex[1] = 1;
pos = 1;
return {1, 0};
}
int l = 1, r = pos;
while (l != r){
int mid = (l+r+1)/2;
if (intersect(node, convex[mid]) >= intersect(convex[mid], convex[mid-1])){
l = mid;
} else {
r = mid-1;
}
}
ll pre = convex[l+1];
convex[l+1] = node;
pos = l+1;
return {l+1, pre};
}
void dfs(int node, int pa = 0){
dp[node] = best(node);
int prevlen = pos;
pair<int, ll> pref = insert(node);
/*
if (node == 3){
cout << pos << ": ";
for (int i = 1; i <= pos; i++){
cout << m(convex[i]) << " " << b(convex[i]) << "\n";
}
cout << "\n";
}*/
for (pair<int, int> nx : edges[node]){
if (nx.f == pa)
continue;
dist[nx.f] = dist[node]+nx.s;
dfs(nx.f, node);
}
convex[pref.f] = pref.s;
pos = prevlen;
}
int main(){
fastIO();
cin >> N;
for (int i = 1; i < N; i++){
int a, b, c; cin >> a >> b >> c;
edges[a].push_back({b, c});
edges[b].push_back({a, c});
}
for (int i = 1; i < N; i++){
cin >> city[i+1].f >> city[i+1].s;
}
dfs(1, 0);
for (int i = 2; i <= N; i++) cout << dp[i] << " ";
cout << "\n";
}
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
Fetching results... |