이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
using namespace std;
typedef long long ll;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int n, m;
cin >> n >> m;
vector<vector<int>> a(n, vector<int>(m, 0));
vector<vector<int>> p(n, vector<int>(m, 0));
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cin >> a[i][j];
}
}
int ans = (int)1e9;
int cnt = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cnt += a[i][j];
if (a[i][j] == 1) {
a[i][j] = -1;
}
else {
a[i][j] = 1;
}
}
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
p[i][j] = a[i][j]
+ (i > 0 ? p[i - 1][j] : 0)
+ (j > 0 ? p[i][j - 1] : 0)
- (i > 0 && j > 0 ? p[i - 1][j - 1] : 0);
}
}
for (int x1 = 0; x1 < n; x1++) {
for (int y1 = 0; y1 < m; y1++) {
for (int x2 = x1; x2 < n; x2++) {
for (int y2 = y1; y2 < m; y2++) {
int cur = p[x2][y2]
- (x1 > 0 ? p[x1 - 1][y2] : 0)
- (y1 > 0 ? p[x2][y1 - 1] : 0)
+ (x1 > 0 && y1 > 0 ? p[x1 - 1][y1 - 1] : 0);
ans = min(ans, cnt + cur);
}
}
}
}
cout << ans << '\n';
return 0;
}
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