//! This is exactly dolphingarlic's submission here: https://oj.uz/submission/238716
//! With the `hyperb` function replaced with $\log(1+\log(1+x))$,
//! which looks similar enough that I wanted to try it.
#include <bits/stdc++.h>
#define FOR(i, x, y) for (int i = x; i < y; i++)
typedef long long ll;
#include "grader.h"
const int SZ = 100, LANGS = 56, MOD = 539653;
ll si[SZ], bi[SZ], tr[SZ], qu[SZ];
double cnt[LANGS];
int freq[LANGS][MOD];
inline double fn(int x) { return log1p(log1p(x)); }
void excerpt(int *E) {
FOR(i, 0, SZ - 3) {
si[i] = E[i];
bi[i] = ((si[i] << 16) + E[i + 1]) % MOD;
tr[i] = ((bi[i] << 16) + E[i + 2]) % MOD;
qu[i] = ((tr[i] << 16) + E[i + 3]) % MOD;
}
int best = 0;
double best_sim = 0;
FOR(i, 0, LANGS) {
double sim = 0;
FOR(j, 0, SZ - 3) {
sim += fn(freq[i][qu[j]]) * 9;
sim += fn(freq[i][tr[j]]) * 1;
sim += fn(freq[i][bi[j]]) * 7;
sim += fn(freq[i][si[j]]) * 1;
}
sim /= log(cnt[i] + 2);
if (sim > best_sim) best = i, best_sim = sim;
}
int ans = language(best);
cnt[ans]++;
FOR(i, 0, SZ - 3) {
freq[ans][qu[i]]++;
freq[ans][tr[i]]++;
freq[ans][bi[i]]++;
freq[ans][si[i]]++;
}
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Execution timed out |
10050 ms |
121332 KB |
Time limit exceeded |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Execution timed out |
10090 ms |
121024 KB |
Time limit exceeded |