Submission #477041

#	Time	Username	Problem	Language	Result	Execution time	Memory
477041		Genius3435	Languages (IOI10_languages)	C++17	0 / 100	10090 ms	121332 KiB

lang

//! This is exactly dolphingarlic's submission here: https://oj.uz/submission/238716
//! With the `hyperb` function replaced with $\log(1+\log(1+x))$,
//! which looks similar enough that I wanted to try it.

#include <bits/stdc++.h>
#define FOR(i, x, y) for (int i = x; i < y; i++)
typedef long long ll;
 
#include "grader.h"
 
const int SZ = 100, LANGS = 56, MOD = 539653;
 
ll si[SZ], bi[SZ], tr[SZ], qu[SZ];
double cnt[LANGS];
int freq[LANGS][MOD];
 
inline double fn(int x) { return log1p(log1p(x)); }
 
void excerpt(int *E) {
    FOR(i, 0, SZ - 3) {
        si[i] = E[i];
        bi[i] = ((si[i] << 16) + E[i + 1]) % MOD;
        tr[i] = ((bi[i] << 16) + E[i + 2]) % MOD;
        qu[i] = ((tr[i] << 16) + E[i + 3]) % MOD;
    }
 
    int best = 0;
    double best_sim = 0;
    FOR(i, 0, LANGS) {
        double sim = 0;
        FOR(j, 0, SZ - 3) {
            sim += fn(freq[i][qu[j]]) * 9;
            sim += fn(freq[i][tr[j]]) * 1;
            sim += fn(freq[i][bi[j]]) * 7;
            sim += fn(freq[i][si[j]]) * 1;
        }
        sim /= log(cnt[i] + 2);
 
        if (sim > best_sim) best = i, best_sim = sim;
    }
 
    int ans = language(best);
    cnt[ans]++;
    FOR(i, 0, SZ - 3) {
        freq[ans][qu[i]]++;
        freq[ans][tr[i]]++;
        freq[ans][bi[i]]++;
        freq[ans][si[i]]++;
    }
}

• Subtask 1: 0 / 30
• Subtask 2: 0 / 80