이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define IO_OP std::ios::sync_with_stdio(0); std::cin.tie(0);
#define F first
#define S second
#define V vector
#define PB push_back
#define MP make_pair
#define EB emplace_back
#define ALL(v) (v).begin(), (v).end()
using namespace std;
typedef long long ll;
typedef pair<int, int> pi;
typedef V<int> vi;
string _reset = "\u001b[0m", _yellow = "\u001b[33m", _bold = "\u001b[1m";
void DBG() { cerr << "]" << _reset << endl; }
template<class H, class...T> void DBG(H h, T ...t) {
cerr << to_string(h);
if(sizeof ...(t)) cerr << ", ";
DBG(t...);
}
#ifdef CHEISSMART
#define debug(...) cerr << _yellow << _bold << "Line(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define debug(...)
#endif
const int INF = 1e9 + 7, N = 2e5 + 7;
void cmax(int& a, int b) {
a = max(a, b);
}
int h[N], a[N], b[N], l[N], r[N], ans[N];
vi G[N];
int n;
int seg_a[N];
struct node {
int base_mx, lz_mx, sum_mx;
node() {
base_mx = lz_mx = sum_mx = -INF;
}
} t[N * 4];
void pull(int v) {
t[v].base_mx = max(t[v * 2].base_mx, t[v * 2 + 1].base_mx);
t[v].sum_mx = max(t[v * 2].sum_mx, t[v * 2 + 1].sum_mx);
}
void apply(int v, int x) {
cmax(t[v].sum_mx, t[v].base_mx + x);
cmax(t[v].lz_mx, x);
}
void push(int v) {
apply(v * 2, t[v].lz_mx);
apply(v * 2 + 1, t[v].lz_mx);
t[v].lz_mx = -INF;
}
void build(int v = 1, int tl = 0, int tr = n) {
t[v] = node();
if(tr - tl == 1) return;
int tm = (tl + tr) / 2;
build(v * 2, tl, tm);
build(v * 2 + 1, tm, tr);
pull(v);
}
void activate(int pos, bool op, int v = 1, int tl = 0, int tr = n) {
if(tr - tl == 1) {
assert(tl == pos);
if(op)
t[v].base_mx = seg_a[pos];
else
t[v].base_mx = -INF;
return;
}
push(v);
int tm = (tl + tr) / 2;
if(pos < tm)
activate(pos, op, v * 2, tl, tm);
else
activate(pos, op, v * 2 + 1, tm, tr);
pull(v);
}
void upd(int l, int r, int x, int v = 1, int tl = 0, int tr = n) {
if(l <= tl && tr <= r) {
apply(v, x);
return;
}
push(v);
int tm = (tl + tr) / 2;
if(l < tm)
upd(l, r, x, v * 2, tl, tm);
if(r > tm)
upd(l, r, x, v * 2 + 1, tm, tr);
pull(v);
}
int qry(int l, int r, int v = 1, int tl = 0, int tr = n) {
if(l <= tl && tr <= r)
return t[v].sum_mx;
push(v);
int tm = (tl + tr) / 2;
int ans = -INF;
if(l < tm)
cmax(ans, qry(l, r, v * 2, tl, tm));
if(r > tm)
cmax(ans, qry(l, r, v * 2 + 1, tm, tr));
return ans;
}
V<pair<int, bool>> ev[N];
signed main()
{
IO_OP;
cin >> n;
for(int i = 0; i < n; i++) {
cin >> h[i] >> a[i] >> b[i];
}
int q;
cin >> q;
for(int i = 0; i < q; i++) {
cin >> l[i] >> r[i];
l[i]--, r[i]--;
ans[i] = -1;
}
auto solve = [&] () {
for(int i = 0; i < q; i++) {
assert(l[i] < r[i]);
G[r[i]].PB(i);
}
for(int i = 0; i < n; i++) {
int L = i + a[i], R = i + b[i];
if(L < n) ev[L].EB(i, true);
if(R + 1 < n) ev[R + 1].EB(i, false);
}
for(int i = 0; i < n; i++) {
seg_a[i] = -h[i];
}
build();
for(int i = 0; i < n; i++) {
for(auto[x, y]:ev[i]) {
activate(x, y);
}
int L = max(0, i - b[i]), R = i - a[i];
if(R >= L)
upd(L, R + 1, h[i]);
for(int j:G[i]) {
assert(r[j] == i);
cmax(ans[j], qry(l[j], i));
}
}
for(int i = 0; i < n; i++) {
G[i].clear();
ev[i].clear();
}
};
solve();
reverse(h, h + n), reverse(a, a + n), reverse(b, b + n);
for(int i = 0; i < q; i++) {
l[i] = n - l[i] - 1, r[i] = n - r[i] - 1;
swap(l[i], r[i]);
}
solve();
for(int i = 0; i < q; i++)
cout << ans[i] << '\n';
}
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