Submission #475551

#	Time	Username	Problem	Language	Result	Execution time	Memory
475551		julian33	Simfonija (COCI19_simfonija)	C++14	0 / 110	39 ms	4884 KiB

simfonija

#include <bits/stdc++.h>

using namespace std;

#ifdef LOCAL
#define deb(...) logger(#__VA_ARGS__, __VA_ARGS__)
template<typename ...Args>
void logger(string vars, Args&&... values) {
    cerr<<vars<<" = ";
    string delim="";
    (...,(cerr<<delim<<values,delim=", "));
    cerr<<"\n";
}
#else
#define deb(...) logger(#__VA_ARGS__, __VA_ARGS__)
template<typename ...Args>
void logger(string vars, Args&&... values) {}
#endif

#define pb push_back
#define sz(x) (int)(x.size())
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
template<typename T> inline void maxa(T& a,T b){a=max(a,b);}
template<typename T> inline void mina(T& a,T b){a=min(a,b);} 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const int mxN=2e5+5; //make sure this is right
const int mod=1e9+7;

int main(){
    cin.sync_with_stdio(0);
    cin.tie(0); cout.tie(0);

    #ifdef LOCAL
        freopen("input.txt","r",stdin);
        freopen("output.txt","w",stdout);
    #endif

    ll n,k; cin>>n>>k;
    vector<ll> a(n),b(n),A(n),psa(n+1);
    for(auto &i:a) cin>>i;
    for(auto &i:b) cin>>i;
    for(int i=0;i<n;i++) A[i]=b[i]-a[i];
    k=n-k;
    sort(A.rbegin(),A.rend());
    for(int i=1;i<=n;i++)
        psa[i]=psa[i-1]+max(0LL,A[i-1]);
    if(k<=1){
        cout<<0<<"\n";
        return 0;
    }
    ll ans=1e18;
    for(int i=k;i<=n;i++){
        int j=i-(k+1)/2+1;
        if(A[j-1]<=0)
            break;
        ll lhs=psa[j-1]-psa[i-k];
        ll rhs=psa[i]-psa[j-1];
        ll r=i-j+1;
        ll l=k-r;
        mina(ans,lhs-l*A[j-1]+r*A[j-1]-rhs);
        deb(i,j,ans,lhs,rhs);
    }
    for(int i=0;i<n;i++) A[i]=-A[i];
    sort(A.rbegin(),A.rend());
    for(int i=1;i<=n;i++)
        psa[i]=psa[i-1]+max(0LL,A[i-1]);
    for(int i=k;i<=n;i++){
        int j=i-(k+1)/2+1;
        if(A[j-1]<=0)
            break;
        ll lhs=psa[j-1]-psa[i-k];
        ll rhs=psa[i]-psa[j-1];
        ll r=i-j+1;
        ll l=k-r;
        mina(ans,lhs-l*A[j-1]+r*A[j-1]-rhs);
        deb(i,ans);
    }
    cout<<ans<<"\n";
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 11
• Subtask 3: 0 / 11
• Subtask 4: 0 / 11
• Subtask 5: 0 / 11
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• Subtask 10: 0 / 11