이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("Ofast")
#include<bits/stdc++.h>
#define FOR(i,a,b) for(int i=a;i<=b;++i)
#define PII pair<int,int>
#define ll long long
#define pb push_back
#define sz(x) (int)(x.size())
#define gc getchar()
#define mk make_pair
//#define gc (_p1==_p2&&(_p2=(_p1=_buf)+fread(_buf,1,100000,stdin),_p1==_p2)?EOF:*_p1++)
using namespace std;
char _buf[100000],*_p1=_buf,*_p2=_buf;
inline int gi()
{
int x=0,f=1;
char ch=gc;
while(ch<'0'||ch>'9')
{
if(ch=='-')f=-1;
ch=gc;
}
while(ch>='0'&&ch<='9')
{
x=(x<<3)+(x<<1)+(ch^48);
ch=gc;
}
return (f==1)?x:-x;
}
const int maxn=3e5+5,M=3e5;
int n,Q,a[maxn],cnt[maxn];
int lp,rp;
inline void input()
{
n=gi();Q=gi();
FOR(i,1,n)a[i]=gi(),cnt[a[i]]++;
sort(cnt+1,cnt+M+1);
}
inline void solve()
{
ll ans=0;
FOR(i,1,M)
{
if(cnt[i]==0)continue;
if(lp>rp)swap(lp,rp);
ans+=1ll*n*(n+1)/2;
ans-=1ll*lp*(lp+1)/2;
ans-=1ll*(n-lp-cnt[i])*(n-lp-cnt[i]+1)/2;
lp+=cnt[i];
}
printf("%lld\n",ans);
}
int main()
{
//freopen("diversity.in","r",stdin);
//freopen("diversity.out","w",stdout);
input();
solve();
return 0;
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |