This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define ll long long
#define pll pair<ll, ll>
#define pii pair<ll, pll>
#define pb push_back
#define fi first
#define se second
using namespace std;
const int N = 2e3+5;
const ll mod = 1e9 + 7;
const int base = 40;
ll n, m, k, t, a[N][N], b[N], tong, dp[N], lab[N], st[N*4], lazy[N*4], ans;
char c;
vector<ll> adj[N], kq;
pll p[N];
ll pw(ll k, ll n)
{
ll total = 1;
for(; n; n >>= 1)
{
if(n & 1)total = total * k % mod;
k = k * k % mod;
}
return total;
}
ll findp(ll u)
{
return lab[u] < 0 ? u : lab[u] = findp(lab[u]);
}
void hop(ll u, ll v)
{
if(lab[u] > lab[v])swap(u, v);
lab[u] += lab[v];
lab[v] = u;
}
void sol()
{
cin >> n >> m;
for(int i = 1; i <= n; i ++)
{
tong = 0;
k = 0;
kq.clear();
for(int j = 1; j <= m; j ++)
{
cin >> c;
if(c == '.')a[i][j] = a[i-1][j] + 1;
while(!kq.empty() && a[i][j] < a[i][kq.back()])
{
ll r = kq.back();
kq.pop_back();
ll l = kq.empty() ? 0 : kq.back();
tong -= (r-l) * (r-1+l) / 2 * a[i][r] * (a[i][r] + 1) / 2;
k -= (r-l) * a[i][r] * (a[i][r]+1)/2;
}
ll l = kq.empty() ? 0 : kq.back();
k += (j-l) * a[i][j] * (a[i][j] + 1) / 2;
tong += (j-l) * (j-1+l) / 2 * a[i][j] * (a[i][j] + 1) / 2;
ans += j * k - tong;
kq.pb(j);
//cout << j*k-tong <<" ";
}
//cout << '\n';
}
cout << ans;
}
int main()
{
cin.tie(0);
cout.tie(0);
ios_base::sync_with_stdio(0);
int test = 1;
//cin >> test;
while (test-- > 0)
sol();
return 0;
}
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