This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int N;
int op(int a, int b)
{
if(a == b) return a;
else return 0+1+2 - a - b;
}
vector<int> op(vector<int> a, vector<int> b)
{
vector<int> r(N);
for(int i = 0; i < N; i++) r[i] = op(a[i], b[i]);
return r;
}
vector<int> to_num(string s)
{
vector<int> r(N);
for(int i = 0; i < N; i++)
{
if(s[i] == 'J') r[i] = 0;
else if(s[i] == 'O') r[i] = 1;
else if(s[i] == 'I') r[i] = 2;
}
return r;
}
vector<int> S[9];
void brute_check(vector<int> G)
{
for(int i = 0; i < 9; i++) if(S[i] == G)
{
cout << "Yes\n";
return;
}
cout << "No\n";
}
int main()
{
cin >> N;
for(int i = 0; i < 3; i++)
{
string T;
cin >> T;
S[i] = to_num(T);
}
S[3] = op(S[1], S[2]);
S[4] = op(S[0], S[2]);
S[5] = op(S[0], S[1]);
S[6] = op(S[0], S[3]);
S[7] = op(S[1], S[4]);
S[8] = op(S[2], S[5]);
// for(int z = 0; z < 9; z++)
// {
// for(int i = 0; i < N; i++) cerr << S[z][i];
// cerr << '\n';
// }
// cerr << '\n';
int Q;
cin >> Q;
string T;
cin >> T;
brute_check(to_num(T));
// for(int i = 0; i < N; i++) cerr << to_num(T)[i];
// cerr << '\n';
for(int q = 1; q <= Q; q++)
{
int L, R;
char C;
cin >> L >> R >> C;
for(int i = L-1; i <= R-1; i++) T[i] = C;
brute_check(to_num(T));
}
}
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