제출 #473747

#제출 시각아이디문제언어결과실행 시간메모리
473747jalsolHarbingers (CEOI09_harbingers)C++17
60 / 100
1088 ms32524 KiB
// looking to shine brighter in this world... #define TASK "harbingers" #ifdef LOCAL #include "local.h" #else #include <bits/stdc++.h> #define debug(...) #define DB(...) #endif using namespace std; using ll = long long; using ld = long double; #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define fi first #define se second #define For(i, l, r) for (int i = (l); i <= (r); ++i) #define Ford(i, r, l) for (int i = (r); i >= (l); --i) #define Rep(i, n) For (i, 0, (n) - 1) #define Repd(i, n) Ford (i, (n) - 1, 0) #define Fe(...) for (auto __VA_ARGS__) template <class C> inline int isz(const C& c) { return static_cast<int>(c.size()); } template <class T> inline bool chmin(T& a, const T& b) { return (a > b) ? a = b, true : false; } template <class T> inline bool chmax(T& a, const T& b) { return (a < b) ? a = b, true : false; } const bool __initialization = []() { cin.tie(nullptr)->sync_with_stdio(false); if (fopen(TASK".inp", "r")) { (void)(!freopen(TASK".inp", "r", stdin)); (void)(!freopen(TASK".out", "w", stdout)); } cout << setprecision(12) << fixed; return true; }(); constexpr ld eps = 1e-9; constexpr int inf = 1e9; constexpr ll linf = 1e18; // ============================================================================= constexpr int maxn = 1e5 + 5; struct Data { int v; ll c; Data() : v(0), c(0) {} Data(int _v, ll _c) : v(_v), c(_c) {} }; struct Town { ll init, speed; Town() : init(0), speed(0) {} Town(ll _i, ll _s) : init(_i), speed(_s) {} }; constexpr long long isCHTQuery = -(1LL << 62); struct Line { long long m, b; mutable std::function<const Line*()> nxt; Line(long long _m, long long _b) : m(_m), b(_b) {} bool operator<(const Line& o) const { if (o.b != isCHTQuery) return m < o.m; const Line* s = nxt(); if (!s) return false; return b - s->b < (s->m - m) * o.m; } }; struct CHT : public std::multiset<Line> { bool bad(iterator y) { if (size() == 1) return false; auto z = next(y); // y is the first line if (y == begin()) { // parallel, y is under z return (y->m == z->m) && (y->b <= z->b); } auto x = prev(y); // y is the last line if (z == end()) { // parallel, y is under x return (y->m == x->m) && (y->b <= x->b); } // x.isect(y) >= y.isect(z) return (x->b - y->b) * (z->m - y->m) >= (y->b - z->b) * (y->m - x->m); } void add(long long m, long long b) { auto y = insert({ m, b }); if (bad(y)) { erase(y); return; } // delete lines on the right while (next(y) != end() && bad(next(y))) { erase(next(y)); } y->nxt = [=] { return next(y) == end() ? 0 : &*next(y); }; // delete lines on the left while (y != begin() && bad(prev(y))) { erase(prev(y)); } if (y != begin()) { prev(y)->nxt = [=] { return &*y; }; } } long long query(long long x) { auto l = *lower_bound(Line(x, isCHTQuery)); return l.m * x + l.b; } }; int n; vector<Data> g[maxn]; Town a[maxn]; ll dist[maxn]; ll dp[maxn]; struct Sub1 { int par[maxn]; void Dfs(int u) { for (int v = par[u]; v; v = par[v]) { chmin(dp[u], dp[v] + a[u].init + a[u].speed * (dist[u] - dist[v])); } Fe (&[v, c] : g[u]) { if (par[v] != -1) continue; par[v] = u; dist[v] = dist[u] + c; Dfs(v); } } void solve() { memset(par + 1, -1, 4 * n); memset(dp + 1, 0x3f, 8 * n); par[1] = 0; dp[1] = 0; Dfs(1); For (i, 2, n) { cout << dp[i] << " \n"[i == n]; } } }; struct Sub2 { CHT hull; void Dfs(int u, int p) { dp[u] = a[u].init + a[u].speed * dist[u] - hull.query(a[u].speed); hull.add(dist[u], -dp[u]); Fe (&[v, c] : g[u]) { if (v == p) continue; dist[v] = dist[u] + c; Dfs(v, u); } } void solve() { // dp[u] + a[v].init + a[v].speed * (dist[v] - dist[u]) // dp[u] + s[v] + v[v] * (d[v] - d[u]) // dp[u] + s[v] + v[v] * d[v] - v[v] * d[u] // s[v] + v[v] * d[v] - v[v] * d[u] + dp[u] // s[v] + v[v] * d[v] + f(v[v]) hull.add(0, 0); Dfs(1, -1); For (i, 2, n) { cout << dp[i] << " \n"[i == n]; } } }; signed main() { cin >> n; int maxi = 0; Rep (_, n - 1) { int u, v; ll c; cin >> u >> v >> c; g[u].emplace_back(v, c); g[v].emplace_back(u, c); chmax(maxi, isz(g[u])); chmax(maxi, isz(g[v])); } For (i, 2, n) cin >> a[i].init >> a[i].speed; if (maxi == 2) { make_unique<Sub2>()->solve(); } else { make_unique<Sub1>()->solve(); } return 0; }
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