oj.uz

답안 #473280

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
473280 2021-09-15T11:15:44 Z _L__ Doktor (COCI17_doktor) C++17
60 / 100
 1000 ms 20956 KB 
// This code is written by _L__
#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
#define F_word ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL);
typedef long long ll;
typedef long double ld;
const int mod = 1e9+7, N = 2e5+13, inf = 1e9+1;
const ld E = 1e-6;
#define ff first
#define ss second
 
int main(void){
    F_word;
    int n; cin >> n;
    int a[n+2] = {}, doc[n+4] = {}; for(int i = 1; i <= n; ++i){cin >> a[i]; doc[a[i]] = a[i]-i;}a[0] = 1;
    if(n <= 500){
        int sum = 0, ans1 = 1, ans2 = 1;
        for(int i = 1; i <= n; ++i){
            for(int j = i; j <= n; ++j){
                reverse(a+i, a+j+1);
                ll x = 0; for(int k = 1; k <= n; ++k) x += (a[k] == k);
                if(x >= sum){
                    ans1 = i, ans2 = j, sum = x;
                }
                reverse(a+i, a+j+1);
            }
        }
        cout << a[ans1] << ' ' << a[ans2] << endl;
        return 0;
    }
    map<int, int> freq_odd, freq_even;
    for(int i = 1; i <= n; ++i)
        if(!(doc[a[i]]%2))
            freq_odd[(i+a[i])/2]++;
    for(int i = 1; i <= n; ++i)
        if(doc[a[i]]%2)
            freq_even[(i+a[i])/2]++;
    ll ans_odd = 0, tar = 0, ans_even = 0;
    for(auto u: freq_odd)
        if(u.ss >= tar)
            {tar = u.ss, ans_odd = u.ff;}
    tar = 0;
    for(auto u: freq_even)
        if(u.ss >= tar)
            {tar = u.ss, ans_even = u.ff;}
    ll a_1 = ans_odd, a_2 = ans_odd, sum = 0, i = ans_odd, j = ans_odd;
    while(i > 0 && j <= n){
        reverse(a+i, a+j+1); ll x = 0;
        for(int k = 1; k <= n; ++k) x += (a[k] == k);
        if(x >= sum){
            a_1 = i, a_2 = j; sum = x;
        }
        reverse(a+i, a+j+1); ++j, --i;
    }
    ll a_3 = ans_even, a_4 = ans_even+1, sum1 = 0; if(a_3 == 0 || a_4 == 0){a_3 = 0, a_4 = 0;} i = a_3, j = a_4;
    while(i > 0 && j <= n){
        reverse(a+i, a+j+1); ll x = 0;
        for(int k = 1; k <= n; ++k) x += (a[k] == k);
        if(x >= sum1){
            a_3 = i, a_4 = j; sum1 = x;
        }
        reverse(a+i, a+j+1); ++j, --i;
    }
    if(sum >= sum1) cout << a[a_1] << ' ' << a[a_2] << endl;
    else cout << a[a_3] << ' ' << a[a_4] << endl;
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 312 KB Output is correct
2 Correct 38 ms 300 KB Output is correct

Subtask #4
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 332 KB Output is correct
2 Correct 4 ms 332 KB Output is correct

Subtask #5
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 20 ms 500 KB Output is correct
2 Correct 7 ms 332 KB Output is correct

Subtask #6
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 19 ms 348 KB Output is correct
2 Correct 1 ms 332 KB Output is correct

Subtask #7
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 113 ms 716 KB Output is correct
2 Execution timed out 1094 ms 2636 KB Time limit exceeded

Subtask #8
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1082 ms 4036 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #9
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1085 ms 20956 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #10
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1088 ms 12412 KB Time limit exceeded
2 Halted 0 ms 0 KB -