This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define ff first
#define ss second
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define lb lower_bound
#define ub upper_bound
#define setbits(x) __builtin_popcountll(x)
#define zrobits(x) __builtin_ctzll(x)
#define sz(v) (int)v.size()
#define ps(y) cout << fixed << setprecision(y)
#define ms(arr, v) memset(arr, v, sizeof(arr))
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define trav(x, v) for(auto &x: v)
#define w(t) int t; cin >> t; while(t--)
#define rep(i, a, b) for(int i = a; i <= b; i++)
#define rrep(i, a, b) for(int i = a; i >= b; i--)
#define rep0(i, n) rep(i, 0, n - 1)
#define rrep0(i, n) rrep(i, n - 1, 0)
#define rep1(i, n) rep(i, 1, n)
#define rrep1(i, n) rrep(i, n, 1)
#define inp(arr, n) rep0(i, n) cin >> arr[i];
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll, ll> pii;
typedef vector<ll> vi;
typedef vector<vi> vvi;
typedef vector<pii> vp;
typedef vector<bool> vb;
typedef vector<string> vs;
typedef map<ll, ll> mii;
typedef map<char, ll> mci;
typedef priority_queue<ll> pq_mx;
typedef priority_queue<ll, vi, greater<>> pq_mn;
typedef tree<ll, null_type, less<>, rb_tree_tag, tree_order_statistics_node_update> pbds;
/*
* find_by_order(i) -> returns an iterator to the element at ith position (0 based)
* order_of_key(i) -> returns the position of element i (0 based)
*/
const int N = 1e5 + 5, M = 2e3 + 5;
const int mod = 1e9 + 7;
//const int mod = 998244353;
const ll inf = 1e18;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
void fio() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
}
ll n, s, Vi[N], wi[N], ki[N], dp[N][M];
ll f(int i, int j) {
if (i == n) return 0;
if (dp[i][j] != -1) return dp[i][j];
ll ans = 0;
for (int x = 0; x <= ki[i] and j + x * wi[i] <= s; x++) ans = max(ans, x * Vi[i] + f(i + 1, j + x * wi[i]));
return dp[i][j] = ans;
}
int main() {
fio();
cin >> s >> n;
rep0(x, n) cin >> Vi[x] >> wi[x] >> ki[x];
ms(dp, -1);
cout << f(0, 0);
return 0;
}
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