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답안 #471796

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
471796 2021-09-10T20:55:02 Z rainboy Ceste (COCI17_ceste) C
160 / 160
 263 ms 476 KB 
/* https://oj.uz/submission/101391 (Benq) */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define N	2000
#define M	2000
#define INF	1e9
#define LINF	0x3f3f3f3f3f3f3f3fLL

long long min(long long a, long long b) { return a < b ? a : b; }

int ii[M], jj[M], aa[M], bb[M];

int *eh[N], eo[N];

void append(int i, int h) {
	int o = eo[i]++;

	if (o >= 2 && (o & o - 1) == 0)
		eh[i] = (int *) realloc(eh[i], o * 2 * sizeof *eh[i]);
	eh[i][o] = h;
}

long long ans[N]; int xx[N], yy[N], n; double dd[N], z;

int pq[N], iq[1 + N], cnt;

int lt(int i, int j) {
	return dd[i] < dd[j];
}

int p2(int p) {
	return (p *= 2) > cnt ? 0 : (p < cnt && lt(iq[p + 1], iq[p]) ? p + 1 : p);
}

void pq_up(int i) {
	int p, q, j;

	for (p = pq[i]; (q = p / 2) && lt(i, j = iq[q]); p = q)
		iq[pq[j] = p] = j;
	iq[pq[i] = p] = i;
}

void pq_dn(int i) {
	int p, q, j;

	for (p = pq[i]; (q = p2(p)) && lt(j = iq[q], i); p = q)
		iq[pq[j] = p] = j;
	iq[pq[i] = p] = i;
}

void pq_add_last(int i) {
	iq[pq[i] = ++cnt] = i;
}

int pq_remove_first() {
	int i = iq[1], j = iq[cnt--];

	if (j != i)
		pq[j] = 1, pq_dn(j);
	pq[i] = 0;
	return i;
}

void solve() {
	int i;

	for (i = 1; i < n; i++)
		dd[i] = INF;
	dd[0] = 0, xx[0] = 0, yy[0] = 0, pq_add_last(0);
	while (cnt) {
		int i, o;

		i = pq_remove_first();
		for (o = eo[i]; o--; ) {
			int h = eh[i][o], j = i ^ ii[h] ^ jj[h], x = xx[i] + aa[h], y = yy[i] + bb[h];
			double d = dd[i] + aa[h] * z + bb[h] * (1 - z);

			if (dd[j] > d) {
				if (dd[j] == INF)
					pq_add_last(j);
				dd[j] = d, xx[j] = x, yy[j] = y, pq_up(j); 
			}
		}
	}
	for (i = 0; i < n; i++)
		if (dd[i] != INF)
			ans[i] = min(ans[i], (long long) xx[i] * yy[i]);
}

int main() {
	int m, h, i, j;

	scanf("%d%d", &n, &m);
	for (i = 0; i < n; i++)
		eh[i] = (int *) malloc(2 * sizeof *eh[i]);
	for (h = 0; h < m; h++) {
		scanf("%d%d%d%d", &ii[h], &jj[h], &aa[h], &bb[h]), ii[h]--, jj[h]--;
		append(ii[h], h), append(jj[h], h);
	}
	memset(ans, 0x3f, n * sizeof *ans);
	z = 0;
	while (1) {
		double z_;

		solve();
		if (z == 1)
			break;
		z_ = 1;
		for (i = 0; i < n; i++) {
			int o;

			if (dd[i] == INF)
				continue;
			for (o = eo[i]; o--; ) {
				int x, y;
				double z1;

				h = eh[i][o], j = i ^ ii[h] ^ jj[h], x = xx[i] + aa[h] - xx[j], y = yy[i] + bb[h] - yy[j];
				if (x == y)
					continue;
				z1 = (double) -y / (x - y);
				if (z1 > z && z_ > z1)
					z_ = z1;
			}
		}
		z = z_;
	}
	for (i = 1; i < n; i++)
		printf("%lld\n", ans[i] == LINF ? -1 : ans[i]);
	return 0;
}

Compilation message

ceste.c: In function 'append':
ceste.c:20:23: warning: suggest parentheses around '-' in operand of '&' [-Wparentheses]
   20 |  if (o >= 2 && (o & o - 1) == 0)
      |                     ~~^~~
ceste.c: In function 'main':
ceste.c:95:2: warning: ignoring return value of 'scanf' declared with attribute 'warn_unused_result' [-Wunused-result]
   95 |  scanf("%d%d", &n, &m);
      |  ^~~~~~~~~~~~~~~~~~~~~
ceste.c:99:3: warning: ignoring return value of 'scanf' declared with attribute 'warn_unused_result' [-Wunused-result]
   99 |   scanf("%d%d%d%d", &ii[h], &jj[h], &aa[h], &bb[h]), ii[h]--, jj[h]--;
      |   ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct

Subtask #2
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 332 KB Output is correct

Subtask #3
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct

Subtask #4
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 332 KB Output is correct

Subtask #5
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 53 ms 420 KB Output is correct
2 Correct 79 ms 392 KB Output is correct
3 Correct 19 ms 332 KB Output is correct

Subtask #6
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 10 ms 356 KB Output is correct
2 Correct 9 ms 372 KB Output is correct
3 Correct 21 ms 420 KB Output is correct

Subtask #7
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 120 ms 440 KB Output is correct
2 Correct 108 ms 452 KB Output is correct
3 Correct 162 ms 420 KB Output is correct

Subtask #8
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 142 ms 400 KB Output is correct
2 Correct 263 ms 436 KB Output is correct
3 Correct 8 ms 460 KB Output is correct

Subtask #9
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 93 ms 400 KB Output is correct
2 Correct 144 ms 468 KB Output is correct
3 Correct 172 ms 472 KB Output is correct

Subtask #10
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 133 ms 432 KB Output is correct
2 Correct 161 ms 472 KB Output is correct
3 Correct 174 ms 476 KB Output is correct