이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.Comparator;
public class clo {
public static void main(String[] args) throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int compNum = Integer.parseInt(read.readLine());
int[][] computers = new int[compNum][];
int maxComputers = 0;
for (int c = 0; c < compNum; c++) {
// core number, clock rate, and price
computers[c] = Arrays.stream(read.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();
maxComputers += computers[c][0];
}
int orderNum = Integer.parseInt(read.readLine());
int[][] orders = new int[orderNum][];
for (int c = 0; c < orderNum; c++) {
// number ordered, min clock rate, and price
orders[c] = Arrays.stream(read.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();
}
// group both the computers and orders into a single transaction array
int[][] possTransactions = new int[compNum + orderNum][];
for (int t = 0; t < possTransactions.length; t++) {
int[] trans;
if (t < compNum) {
trans = computers[t];
if (trans[2] <= 0) {
throw new IllegalArgumentException("the price of a computer has to be positive");
}
trans[2] = -trans[2];
} else {
trans = orders[t - compNum];
if (trans[2] <= 0) {
throw new IllegalArgumentException("the budget of a consumer has to be positive");
}
}
possTransactions[t] = trans;
}
// if we sort like this, then the entire clock rate issue goes away as long as we process them in order
Arrays.sort(possTransactions, Comparator.comparingInt(t -> -t[1]));
long[] maxProfits = new long[maxComputers + 1];
Arrays.fill(maxProfits, Long.MIN_VALUE);
maxProfits[0] = 0;
for (int[] t : possTransactions) {
long[] newMax = maxProfits.clone();
if (t[2] < 0) { // we buy some computers
for (int c = 1; c <= maxComputers; c++) {
if (t[0] <= c && maxProfits[c - t[0]] != Long.MIN_VALUE) {
newMax[c] = Math.max(newMax[c], maxProfits[c - t[0]] + t[2]);
}
}
} else { // or we sell some, it depends on the price
for (int c = 1; c <= maxComputers; c++) {
if (c + t[0] <= maxComputers && maxProfits[c + t[0]] != Long.MIN_VALUE) {
newMax[c] = Math.max(newMax[c], maxProfits[c + t[0]] + t[2]);
}
}
}
maxProfits = newMax;
}
System.out.println(Arrays.stream(maxProfits).max().getAsLong());
}
}
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