이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
*/
using namespace std;
// using namespace __gnu_pbds;
using namespace chrono;
// mt19937 rng((int) std::chrono::steady_clock::now().time_since_epoch().count());
/*
template <class T> using ordered_set = tree <T, null_type, less <T>, rb_tree_tag, tree_order_statistics_node_update>;
*/
//***************** CONSTANTS *****************
const int MXN = 100000;
const int K = 17;
const int64_t INF = 1000000000000000000;
//***************** GLOBAL VARIABLES *****************
vector<array<int, 2>> g[MXN];
int N, S, Q, root;
int up[K][MXN], tin[MXN], tout[MXN], timer;
int64_t s[MXN], D[MXN], mn[K][MXN];
array<int, 2> e[MXN];
//***************** AUXILIARY STRUCTS *****************
void dfs(int u, int p, int64_t d){
tin[u] = timer++;
D[u] = d;
for(auto& [v, w] : g[u]) if(v != p){
dfs(v, u, d + w);
s[u] = min(s[u], s[v] + w);
}
tout[u] = timer++;
}
void calc(int u, int p){
up[0][u] = p;
mn[0][u] = min(s[u] - D[u], s[p] - D[p]);
for(int i = 1; i < K; i++){
up[i][u] = up[i-1][up[i-1][u]];
mn[i][u] = min(mn[i-1][u], mn[i-1][up[i-1][u]]);
}
for(auto& [v, w] : g[u]) if(v != p){
calc(v, u);
}
}
inline bool is_ancestor(int u, int k, int v){
u = up[k][u];
return tin[u] < tin[v] && tout[u] > tout[v];
}
//***************** MAIN BODY *****************
void solve(){
cin >> N >> S >> Q >> root;
--root;
for(int i = 0; i < N - 1; i++){
int u, v, w;
cin >> u >> v >> w;
--u, --v;
g[u].push_back({v, w});
g[v].push_back({u, w});
e[i] = {u, v};
}
fill(s, s + N, INF);
for(int i = 0; i < S; i++){
int u;
cin >> u;
--u;
s[u] = 0;
}
dfs(root, root, 0);
calc(root, root);
for(int i = 0; i < N; i++)
cout << D[i] << ' ' << s[i] << '\n';
for(int _ = 0; _ < Q; _++){
int x, u;
cin >> x >> u;
--x, --u;
if(tin[e[x][0]] > tin[e[x][1]])
swap(e[x][0], e[x][1]);
x = e[x][1];
if(tin[x] <= tin[u] && tout[x] >= tout[u]){
int64_t ans = s[u] - D[u];
int y = u;
for(int i = K - 1; i >= 0; --i)
if(!is_ancestor(u, i, x)){
ans = min(ans, mn[i][u]);
u = up[i][u];
}
if(ans + D[u] >= INF) cout << "oo\n";
else cout << ans + D[y] << '\n';
}
else cout << "escaped\n";
}
}
//***************** *****************
int32_t main(){
ios_base::sync_with_stdio(NULL);
cin.tie(NULL);
#ifdef LOCAL
auto begin = high_resolution_clock::now();
#endif
int tc = 1;
// cin >> tc;
for (int t = 0; t < tc; t++)
solve();
#ifdef LOCAL
auto end = high_resolution_clock::now();
cout << fixed << setprecision(4);
cout << "Execution Time: " << duration_cast<duration<double>>(end - begin).count() << "seconds" << endl;
#endif
return 0;
}
/*
If code gives a WA, check for the following :
1. I/O format
2. Are you clearing all global variables in between tests if multitests are a thing
3. Can you definitively prove the logic
4. If the code gives an inexplicable TLE, and you are sure you have the best possible complexity,
use faster io
*/
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