This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define fast ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL)
#define ll long long int
#define ld long double
using namespace std;
const int N = 2e2 + 5;
const int MOD = 1e9 + 7;
vector<int> graph[N];
int n, k, a[N], dp[N][N];
void dfs(int node, int par){
dp[node][0] = a[node];
for(auto kk : graph[node]){
if(kk == par) continue;
dfs(kk, node);
}
for(int depth = 0; depth <= n; ++depth){
if(!depth){
for(auto kk : graph[node]){
if(kk == par) continue;
dp[node][depth] += dp[kk][max(0, k - depth - 1)];
}
continue;
}
for(auto kk : graph[node]){
if(kk == par) continue;
int cur = dp[kk][depth - 1];
for(auto j : graph[node]){
if(j == kk or j == par) continue;
cur += dp[j][max(k - depth - 1, depth - 1)];
}
dp[node][depth] = max(dp[node][depth], cur);
}
}
for(int depth = n; depth > 0; --depth)
dp[node][depth - 1] = max(dp[node][depth - 1] , dp[node][depth]);
}
void solve(){
cin >> n >> k;
for(int i = 1; i <= n; ++i)
a[i] = 1;
for(int i = 2; i <= n; ++i){
int p;
cin >> p;
++p;
graph[i].push_back(p);
graph[p].push_back(i);
}
// let dp[i][depth] be the max sum of subset of vertices that we can take from the subtree
// of v such that the minimum depth of a selected node is atleast depth.
dfs(1, 0);
cout << dp[1][0] << '\n';
}
int main(){
fast;
int t = 1;
// cin >> t;
while(t--)
solve();
return 0;
// you should actually read the stuff at the bottom
}
/* stuff you should look for
* int overflow, array bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH
* Read other problems if stuck on this one.
*/
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