Submission #470739

#TimeUsernameProblemLanguageResultExecution timeMemory
470739sumit_kk10Cat in a tree (BOI17_catinatree)C++14
11 / 100
1 ms460 KiB
#include <bits/stdc++.h> #define fast ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL) #define ll long long int #define ld long double using namespace std; const int N = 2e2 + 5; const int MOD = 1e9 + 7; vector<int> graph[N]; int n, k, a[N], dp[N][N]; void dfs(int node, int par){ dp[node][0] = a[node]; for(auto kk : graph[node]){ if(kk == par) continue; dfs(kk, node); } for(int depth = 0; depth <= n; ++depth){ if(!depth){ for(auto kk : graph[node]){ if(kk == par) continue; dp[node][depth] += dp[kk][max(0, k - depth - 1)]; } continue; } for(auto kk : graph[node]){ if(kk == par) continue; int cur = dp[kk][depth - 1]; for(auto j : graph[node]){ if(j == kk or j == par) continue; cur += dp[j][max(k - depth - 1, depth - 1)]; } dp[node][depth] = max(dp[node][depth], cur); } } for(int depth = n; depth > 0; --depth) dp[node][depth - 1] = max(dp[node][depth - 1] , dp[node][depth]); } void solve(){ cin >> n >> k; for(int i = 1; i <= n; ++i) a[i] = 1; for(int i = 2; i <= n; ++i){ int p; cin >> p; ++p; graph[i].push_back(p); graph[p].push_back(i); } // let dp[i][depth] be the max sum of subset of vertices that we can take from the subtree // of v such that the minimum depth of a selected node is atleast depth. dfs(1, 0); cout << dp[1][0] << '\n'; } int main(){ fast; int t = 1; // cin >> t; while(t--) solve(); return 0; // you should actually read the stuff at the bottom } /* stuff you should look for * int overflow, array bounds * special cases (n=1?) * do smth instead of nothing and stay organized * WRITE STUFF DOWN * DON'T GET STUCK ON ONE APPROACH * Read other problems if stuck on this one. */
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