제출 #470076

#제출 시각아이디문제언어결과실행 시간메모리
470076BlancaHMTraffic (IOI10_traffic)C++14
100 / 100
1262 ms170716 KiB
#include <iostream> #include <vector> using namespace std; typedef long long int ll; ll dfs(int S, int parent, vector<vector<int>> & adjList, vector<ll> & DP) { for (int v: adjList[S]) { if (v == parent) continue; DP[S] += dfs(v, S, adjList, DP); } // DP[S] contains the total population in the subtree of S return DP[S]; } int LocateCentre(int N, int P[], int S[], int D[]) { vector<ll>DP(N); vector<vector<int>> adjList(N, vector<int>()); for (int i = 0; i < N-1; i++) { // we convert the graph format to an adjacency list adjList[S[i]].emplace_back(D[i]); adjList[D[i]].emplace_back(S[i]); } for (int i = 0; i < N; i++) DP[i] = P[i]; // we initialise the DP so that it contains each city's population dfs(0, -1, adjList, DP); // we choose 0 originally as our city with lowest maximum congestion and find its largest congestion int chosenCity = 0; ll chosenCityMaxCongestion = 0; for (int rootNeighbour: adjList[0]) { chosenCityMaxCongestion = max(chosenCityMaxCongestion, DP[rootNeighbour]); } // we iterate over all possible chosen cities and compare them with the current record for (int currentCity = 1; currentCity < N; currentCity++) { // before comparing with the congestion coming from children nodes, we will take as the maximum the congestion travelling from the currentCity's parent to the currentCity ll currentCityMaxCongestion = DP[0] - DP[currentCity]; // we now iterate over the currentCity's children nodes to see if the congestion from a child to the currentCity is higher than that from the parent for (int v: adjList[currentCity]) { if (DP[v] < DP[currentCity]) currentCityMaxCongestion = max(currentCityMaxCongestion, DP[v]); } // if the city's maximum congestion is lower than the current record, we update it if (currentCityMaxCongestion < chosenCityMaxCongestion) { chosenCityMaxCongestion = currentCityMaxCongestion; chosenCity = currentCity; } } return chosenCity; }
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