이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#define ll int
#define ld long double
#define fs first
#define sc second
#define debug(y) cout<<y,exit(0)
using namespace std;
typedef pair<ll,ll> LL;
const ll N = 1e6 + 9;
const ll mod = 998244353;
ll n,a[N],pre[N],val[N],take,ans;
ll cal(ll l,ll r){
//cout<<pre[r]<<" "<<pre[n] - pre[l - 1]; exit(0);
if (l <= r) return pre[r] - pre[l - 1];
return pre[r] + pre[n] - pre[l - 1];
}
int main(){
ios_base::sync_with_stdio(NULL); cin.tie(0); cout.tie(0);
#define task "tst"
if (fopen(task".inp","r")){
freopen(task".inp","r",stdin);
//freopen(task".out","w",stdout);
}
cin>>n; take = (n + 1)/2;
for (ll i = 1;i <= n;i++) cin>>a[i],pre[i] = pre[i - 1] + a[i];
//cout<<cal(4,1)<<"x"; return 0;
for (ll i = 1;i <= n;i++){
ll l = i,r = i + take - 1; if (r > n) r -= n;
//cout<<l<<" "<<r<<" "<<cal(l,r)<<"\n";
val[i] = cal(l,r);
}
for (ll i = n + 1;i <= 2*n;i++) val[i] = val[i - n];
//for (ll i = 1;i <= n;i++) cout<<val[i]<<" "; return 0;
deque<ll> dq;
for (ll i = 1;i <= 2*n;i++){
while(!dq.empty() && val[i] <= val[dq.back()]) dq.pop_back();
while(!dq.empty() && i - dq.front() + 1 > take) dq.pop_front();
dq.push_back(i); ans = max(ans,val[dq.front()]);
}
cout<<ans;
}
/* stuff you should look for
* int overflow,array bound
* special cases (n = 1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH
*/
컴파일 시 표준 에러 (stderr) 메시지
hac.cpp: In function 'int main()':
hac.cpp:25:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
25 | freopen(task".inp","r",stdin);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
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