Submission #46983

#TimeUsernameProblemLanguageResultExecution timeMemory
46983nickyrioChase (CEOI17_chase)C++17
70 / 100
958 ms186332 KiB
#include <bits/stdc++.h> #define FOR(i, a, b) for (int i = (a); i <= (b); ++i) #define FORD(i, a, b) for (int i = (a); i >= (b); --i) #define REP(i, a) for (int i = 0; i < (a); ++i) #define DEBUG(x) { cerr << #x << '=' << x << endl; } #define Arr(a, l, r) { cerr << #a << " = {"; FOR(_, l, r) cerr << ' ' << a[_]; cerr << "}\n"; } #define N 100100 #define pp pair<int, int> #define endl '\n' #define IO ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL) #define taskname "" #define bit(S, i) (((S) >> (i)) & 1) void Max(long long &a, long long b) { a = a < b ? b : a; } void Min(long long &a, long long b) { a = a < b ? a : b; } using namespace std; int n, k; vector<int> e[N]; long long ans, a[N], DtoU[N][111], UtoD[N][111], sum[N]; void dfs(int u, int p) { DtoU[u][1] = sum[u]; /*FOR(i, 1, k) { // Choose u if (i != 1 && p != -1) Max(UtoD[u][i], UtoD[p][] }*/ for (int v : e[u]) if (v != p) { FOR(i, 1, k) { // Choose v if (i != 1) Max(UtoD[v][i], UtoD[u][i - 1] + sum[v] - a[u]); else UtoD[v][i] = sum[v] - a[u]; // Don't choose v Max(UtoD[v][i], UtoD[u][i]); Max(ans, UtoD[v][i]); } dfs(v, u); FOR(i, 1, k) { // Choose u if (i != 1) Max(DtoU[u][i], DtoU[v][i - 1] + sum[u] - a[v]); // Don't choose u Max(DtoU[u][i], DtoU[v][i]); } } } int main() { #ifdef NERO freopen("test.inp","r",stdin); freopen("test.out","w",stdout); double stime = clock(); #else //freopen(taskname".inp","r",stdin); //freopen(taskname".out","w",stdout); #endif //NERO IO; cin >> n >> k; FOR(i, 1, n) cin >> a[i]; FOR(i, 2, n) { int u, v; cin >> u >> v; e[u].push_back(v); e[v].push_back(u); } if (k == 0) { cout << 0; return 0; } FOR(u, 1, n) { for (int v : e[u]) sum[u] += a[v]; } //Arr(sum, 1, n); ans = 0; if (n > 1000) { dfs(1, -1); UtoD[1][1] = sum[1]; dfs(1, -1); } else { FOR(root, 1, n) { FOR(i, 1, n) FOR(j, 1, k) UtoD[i][j] = DtoU[i][j] = 0; UtoD[root][1] = sum[root]; dfs(root, -1); } } cout << ans; #ifdef NERO double etime = clock(); cerr << "\nExecution time: " << (etime - stime) / CLOCKS_PER_SEC * 1000 << " ms.\n"; #endif // NERO }
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