이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#ifdef DEBUG
#define dbg(...) printf(__VA_ARGS__);
#else
#define dbg(...)
#endif
#define sf scanf
#define pf printf
#define fi first
#define se second
#define pb emplace_back
#define ppb pop_back
#define sz(x) (int)x.size()
#define mnto(x,y) x=min(x,(__typeof__(x))y)
#define mxto(x,y) x=max(x,(__typeof__(x))y)
#define INF 1023456789
#define LINF 1023456789123456789
#define all(x) x.begin(), x.end()
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
typedef tuple<int, int, int, int> iiii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<pll> vll;
mt19937 rng(time(0));
int n;
ll a,b,pfx[500005],val[500005];
vll v;
int main(){
sf("%d",&n);
v.resize(n+1);
for(int i=1;i<=n;++i){
sf("%lld%lld",&v[i].fi,&v[i].se);
}
sort(all(v));
ll mn=LINF,ans=-LINF;
for(int i=1;i<=n;++i){
pfx[i]=pfx[i-1]+v[i].se;
val[i-1]=pfx[i-1]-v[i].fi;
mnto(mn,val[i-1]);
mxto(ans,pfx[i]-v[i].fi-mn);
}
pf("%lld\n",ans);
}
컴파일 시 표준 에러 (stderr) 메시지
art.cpp: In function 'int main()':
art.cpp:37:4: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
37 | sf("%d",&n);
| ^
art.cpp:40:5: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
40 | sf("%lld%lld",&v[i].fi,&v[i].se);
| ^
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