Submission #46646

#	Time	Username	Problem	Language	Result	Execution time	Memory
46646		qoo2p5	Soccer (JOI17_soccer)	C++17	0 / 100	248 ms	5524 KiB

soccer

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

const int INF = (int) 1e9 + 1e6 + 123;
const ll LINF = (ll) 1e18 + 1e9 + 123;

#define rep(i, s, t) for (auto i = (s); i < (t); ++(i))
#define per(i, s, t) for (auto i = (s); i >= (t); --(i))
#define all(x) (x).begin(), (x).end()
#define sz(x) ((int)(x).size())
#define mp make_pair
#define pb push_back

bool mini(auto &x, const auto &y) {
    if (y < x) {
        x = y;
        return 1;
    }
    return 0;
}

bool maxi(auto &x, const auto &y) {
    if (y > x) {
        x = y;
        return 1;
    }
    return 0;
}

void run();

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    run();
    return 0;
}

const int N = (int) 1e5 + 123;
const int K = 505;

int h, w;
ll a, b, c;
int n;
int x[N], y[N];
int dist[K][K];
ll dp[K][K][2];

const int dx[4] = {-1, 1, 0, 0};
const int dy[4] = {0, 0, -1, 1};

void run() {
    cin >> h >> w;
    cin >> a >> b >> c;
    cin >> n;
    rep(i, 0, n) {
        cin >> x[i] >> y[i];
    }
    rep(i, 1, n) {
        x[i] -= x[0];
        y[i] -= y[0];
    }
    x[0] = 0;
    y[0] = 0;
    
    int mX = *min_element(x, x + n);
    int mY = *min_element(y, y + n);
    rep(i, 0, n) {
        x[i] -= mX;
        y[i] -= mY;
    }
    
    {
        queue<pair<int, int>> q;
        rep(i, 0, K) rep(j, 0, K) dist[i][j] = INF;
        rep(i, 0, n) {
            q.push({x[i], y[i]});
            dist[x[i]][y[i]] = 0;
        }
        while (sz(q)) {
            auto v = q.front();
            q.pop();
            rep(dir, 0, 4) {
                int nx = v.first + dx[dir];
                int ny = v.second + dy[dir];
                if (0 <= nx && nx < K && 0 <= ny && ny < K && mini(dist[nx][ny], dist[v.first][v.second] + 1)) {
                    q.push({nx, ny});
                }
            }
        }
    }
    
    rep(i, 0, K) rep(j, 0, K) rep(t, 0, 2) dp[i][j][t] = LINF;
    dp[x[0]][y[0]][1] = 0;
    
    ll ans = LINF;
    
    rep(i, 0, K - 1) {
        rep(j, 0, K - 1) {
            mini(dp[i][j][1], dp[i][j][0] + dist[i][j] * c);
            mini(dp[i + 1][j][1], dp[i][j][1] + c);
            mini(dp[i][j + 1][1], dp[i][j][1] + c);
            rep(t, 1, K) {
                if (i + t >= K) {
                    break;
                }
                mini(dp[i + t][j][0], dp[i][j][1] + b + a * t);
            }
            rep(t, 1, K) {
                if (j + t >= K) {
                    break;
                }
                mini(dp[i][j + t][0], dp[i][j][1] + b + a * t);
            }
            
            rep(t, 0, 2) {
                mini(ans, dp[i][j][t] + c * (abs(x[n - 1] - i) + abs(y[n - 1] - j)));
            }
        }
    }
    
    cout << ans << "\n";
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 30
• Subtask 3: 0 / 65