제출 #466192

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
466192		AmirElarbi	어르신 집배원 (BOI14_postmen)	C++14	0 / 100	1092 ms	332 KiB

postmen

#include <bits/stdc++.h>
#define vi vector<int>
#define ve vector
#define ll long long
#define vf vector<float>
#define vll vector<pair<ll,ll>>
#define ii pair<int,int>
#define vvi vector<vi>
#define vii vector<ii>
#define gii greater<ii>
#define pb push_back
#define fi first
#define se second
#define INF 1e7
#define unsigned u
#define eps 1e-18
#define eps1 1e-25
#define optimise ios_base::sync_with_stdio(false);cin.tie(NULL);
#define MAX_A 100005
#define V 450
#define re register
#define maxi(a,b) ((a) > (b) ? (a) : (b))
using namespace std;
vii adj[2005];
bool vis[100005];
int tv[2005];
int n,m,used;
bool dfs(int u, int p){
    //cout << u  << " " << used  << endl;
    tv[u] = 1;
    for(auto x : adj[u])
    {
        if(x.fi == p)
            continue;
        if(vis[x.se])
            continue;
         //cout << tv[x.fi] << endl;
        if(tv[x.fi]){
            vis[x.se] = true;
            used++;
            tv[x.fi] = 2;
            tv[u] = 0;
            cout << u << " ";
            return true;
        }
        vis[x.se] = true;
        used++;
        if(dfs(x.fi,u)){
            cout << u << " ";
            //cout << tv[u] << endl;
            if(tv[u] == 2){
                tv[u] = 0;
                cout << endl;
                vis[x.se] = 0;
                used--;
                //cout << x.se << endl;
                continue;
            }
            return true;
        }
        vis[x.se] = 0;
        used--;
    }
    return false;
}
int main(){
    optimise;
    cin >> n >> m;
    for (int i = 0; i < m; ++i)
    {
        int a,b;
        cin >> a >>b;
        adj[a].pb({b,i});
        adj[b].pb({a,i});
    }
    int d = 1;
    while (used != m)
    {
        for (int i = 1; i <= n; ++i)
        { 
            memset(tv, 0, sizeof tv);
            if(dfs(i,-1)){
                
                break;
            }  else 
                d++;
        }
        //cout << tv[1] << endl;
    }
}

• Subtask 1: 0 / 38
• Subtask 2: 0 / 17
• Subtask 3: 0 / 45