이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*THINK GONNA FAIL ? IF U DIDNT FAIL THEN WHAT IS THE POINT OF LEARNING */
#include <bits/stdc++.h>
#define ll long long
#define pii pair<long long, long long>
#define ull unsigned long long
#define st first
#define nd second
#define lower_case_alphabet "abcdefghijklmnopqrstuvwxyz"
#define upper_case_alphabet "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
#define file "test"
using namespace std;
const long long oo = 1e18;
const long long N = 1e5 + 5;
ll n, cnt, dp[N], A[N];
int s;
vector <pii> d[2004];
void decompose(int x){
if (x == 0){
cnt = -1;
return;
}
cnt = 0;
ll sum = 1;
while (x > sum){
x -= sum;
A[cnt++] = sum;
sum <<= 1;
}
A[cnt] = x;
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
cin >> s >> n;
for (int i = 1, v, w, k; i <= n; i ++){
cin >> v >> w >> k;
k = min(k, s/w + 1);
d[w].push_back({v, k});
}
for (int i = 1; i <= s; i ++)
if (d[i].size()){
sort(d[i].begin(), d[i].end(), greater<pii> ());
int out = 0;
for (pii p: d[i]){
if (s/i < out) break;
out ++;
decompose(p.nd);
for (ll W, V; cnt >= 0; cnt --){
W = A[cnt]*i, V = A[cnt]*p.st;
for (int j = s; j >= W; j --)
dp[j] = max(dp[j], dp[j-W] + V);
}
}
}
cout << dp[s];
return 0;
}
// sketch out every idea before see any solution, it helps alots.
/** /\_/\
* (= ._.)
* / >0 \>1
**/
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