oj.uz

답안 #45472

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
45472 2018-04-14T10:16:27 Z RayaBurong25_1 Palembang Bridges (APIO15_bridge) C++17
22 / 100
 337 ms 13832 KB 
#include <stdio.h>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
#include <cassert>
#define INF 1000000000000000000LL
typedef struct node node;
struct node
{
    int s, e;
};
std::set<long long> Event;
std::vector<long long> cEvent;
std::vector<node> incE, decS;
long long abs(long long a)
{
    return (a < 0)?-a:a;
}
long long min(long long a, long long b)
{
    return (a < b)?a:b;
}
long long max(long long a, long long b)
{
    return (a > b)?a:b;
}
int sortIncE(node a, node b)
{
    return (a.e < b.e || (a.e == b.e && a.s < b.s));
}
int sortDecS(node a, node b)
{
    return (a.s > b.s || (a.s == b.s && a.e > b.e));
}
typedef struct se se;
struct se
{
    long long sum;
    int i;
};
bool operator<(se a, se b)
{
    return (a.sum < b.sum || (a.sum == b.sum && a.i < b.i));
}
std::map<se, int> SE;
std::map<se, int>::iterator p, q;
int main()
{
    int K, N;
    scanf("%d %d", &K, &N);
    int i, j, k;
    int i2, j2, k2;
    long long Obligatory = 0;
    long long Sum1a = 0, Sum1b = 0;
    long long Sum2a = 0, Sum2b = 0, Sum2c = 0;
    char P, Q;
    int S, T;
    for (i = 0; i < N; i++)
    {
        scanf(" %c %d %c %d", &P, &S, &Q, &T);
        if (P == Q)
        {
            Obligatory += abs(T - S);
        }
        else
        {
            Obligatory += 1 + abs(T - S);
            incE.push_back({min(S, T), max(S, T)});
            decS.push_back({min(S, T), max(S, T)});
            Event.insert(S);
            Event.insert(T);
        }
    }
    // printf("Obligatory %lld\n", Obligatory);
    std::set<long long>::iterator it;
    for (it = Event.begin(); it != Event.end(); it++)
    {
        cEvent.push_back(*it);
        // printf("cEvent %lld\n", *it);
    }
    N = incE.size();
    for (i = 0; i < N; i++)
    {
        S = std::lower_bound(cEvent.begin(), cEvent.end(), incE[i].s) - cEvent.begin();
        T = std::lower_bound(cEvent.begin(), cEvent.end(), incE[i].e) - cEvent.begin();
        incE[i] = {S, T};
        S = std::lower_bound(cEvent.begin(), cEvent.end(), decS[i].s) - cEvent.begin();
        T = std::lower_bound(cEvent.begin(), cEvent.end(), decS[i].e) - cEvent.begin();
        decS[i] = {S, T};
        // printf("S%d T%d\n", S, T);
        Sum1b += cEvent[S];
    }
    std::sort(incE.begin(), incE.end(), sortIncE);
    std::sort(decS.begin(), decS.end(), sortDecS);

    if (K == 2)
    {
        long long Ans = INF;
        if (cEvent.size() == 0)
            Ans = Obligatory;
        j = 0;
        k = N - 1;
        for (i = 0; i < cEvent.size(); i++)
        {
            while (j < N && incE[j].e < i)
            {
                Sum1a += cEvent[incE[j].e];
                SE.insert({{cEvent[incE[j].s] + cEvent[incE[j].e], j}, 0});
                j++;
            }
            while (k >= 0 && decS[k].s == i)
            {
                Sum1b -= cEvent[decS[k].s];
                k--;
            }
            j2 = 0;
            k2 = j - 1;
            p = SE.begin();
            Sum2a = 0;
            Sum2b = 0;
            Sum2c = 0;
            for (i2 = 0; i2 < i; i2++)
            {
                while (p != SE.end() && p->first.sum < cEvent[i] + cEvent[i2])
                {
                    if (p->first.i <= k2)
                    {
                        p->second = 1;
                        Sum2c += 2LL*(cEvent[i] + cEvent[i2] - p->first.sum);
                    }
                    p++;
                }
                while (k2 >= 0 && decS[k2].s == i2)
                {
                    q = SE.find({cEvent[decS[k2].s] + cEvent[decS[k2].e], k2});
                    if (q->second == 1)
                    {
                        Sum2c -= 2LL*(cEvent[i] + cEvent[i2] - q->first.sum);
                        q->second = 0;
                    }
                    Sum2b += 2LL*(cEvent[i] - cEvent[decS[k2].e]);
                    k2--;
                }
                while (j2 < j && incE[j2].e < i2)
                {
                    Sum2b -= 2LL*(cEvent[i] - cEvent[incE[j2].e]);
                    Sum2a += 2LL*(cEvent[i] - cEvent[i2]);
                    j2++;
                }
                assert(Sum2a >= 0 && Sum2b >= 0 && Sum2c >= 0);
                // printf("i2 %d j2 %d k2 %d Sum1a %lld Sum1b %lld Sum2a %lld Sum2b %lld Sum2c %lld = %lld\n", i2, j2, k2, Sum1a, Sum1b, Sum2a, Sum2b, Sum2c, Obligatory + 2LL*(cEvent[i]*j - Sum1a) + 2LL*(Sum1b - cEvent[i]*(k + 1)) - Sum2a - Sum2b - Sum2c);
                Ans = min(Ans, Obligatory + 2LL*(cEvent[i]*j - Sum1a) + 2LL*(Sum1b - cEvent[i]*(k + 1)) - Sum2a - Sum2b - Sum2c);
            }
            // printf("i %d j %d k %d Sum1a %lld Sum1b %lld = %lld\n", i, j, k, Sum1a, Sum1b, Obligatory + 2LL*(cEvent[i]*j - Sum1a) + 2LL*(Sum1b - cEvent[i]*(k + 1)));
            Ans = min(Ans, Obligatory + 2LL*(cEvent[i]*j - Sum1a) + 2LL*(Sum1b - cEvent[i]*(k + 1)));
        }
        printf("%lld", Ans);
    }
    else
    {
        long long Ans = INF;
        if (cEvent.size() == 0)
            Ans = Obligatory;
        j = 0;
        k = N - 1;
        for (i = 0; i < cEvent.size(); i++)
        {
            while (j < N && incE[j].e < i)
            {
                Sum1a += cEvent[incE[j].e];
                j++;
            }
            while (k >= 0 && decS[k].s == i)
            {
                Sum1b -= cEvent[decS[k].s];
                k--;
            }
            // printf("j %d k %d Sum1a %lld Sum1b %lld = %lld\n", j, k, Sum1a, Sum1b, Obligatory + 2LL*(cEvent[i]*j - Sum1a) + 2LL*(Sum1b - cEvent[i]*(k + 1)));
            Ans = min(Ans, Obligatory + 2LL*(cEvent[i]*j - Sum1a) + 2LL*(Sum1b - cEvent[i]*(k + 1)));
        }
        printf("%lld", Ans);
    }
}

Compilation message

bridge.cpp: In function 'int main()':
bridge.cpp:69:32: warning: narrowing conversion of 'min(((long long int)S), ((long long int)T))' from 'long long int' to 'int' inside { } [-Wnarrowing]
             incE.push_back({min(S, T), max(S, T)});
                             ~~~^~~~~~
bridge.cpp:69:43: warning: narrowing conversion of 'max(((long long int)S), ((long long int)T))' from 'long long int' to 'int' inside { } [-Wnarrowing]
             incE.push_back({min(S, T), max(S, T)});
                                        ~~~^~~~~~
bridge.cpp:70:32: warning: narrowing conversion of 'min(((long long int)S), ((long long int)T))' from 'long long int' to 'int' inside { } [-Wnarrowing]
             decS.push_back({min(S, T), max(S, T)});
                             ~~~^~~~~~
bridge.cpp:70:43: warning: narrowing conversion of 'max(((long long int)S), ((long long int)T))' from 'long long int' to 'int' inside { } [-Wnarrowing]
             decS.push_back({min(S, T), max(S, T)});
                                        ~~~^~~~~~
bridge.cpp:104:23: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for (i = 0; i < cEvent.size(); i++)
                     ~~^~~~~~~~~~~~~~~
bridge.cpp:167:23: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for (i = 0; i < cEvent.size(); i++)
                     ~~^~~~~~~~~~~~~~~
bridge.cpp:51:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d", &K, &N);
     ~~~~~^~~~~~~~~~~~~~~~~
bridge.cpp:61:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf(" %c %d %c %d", &P, &S, &Q, &T);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 256 KB Output is correct
2 Correct 2 ms 360 KB Output is correct
3 Correct 2 ms 428 KB Output is correct
4 Correct 3 ms 732 KB Output is correct
5 Correct 4 ms 732 KB Output is correct
6 Correct 2 ms 732 KB Output is correct
7 Correct 3 ms 732 KB Output is correct
8 Correct 3 ms 732 KB Output is correct
9 Correct 3 ms 732 KB Output is correct
10 Correct 2 ms 732 KB Output is correct
11 Correct 4 ms 732 KB Output is correct

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 732 KB Output is correct
2 Correct 2 ms 732 KB Output is correct
3 Correct 3 ms 732 KB Output is correct
4 Correct 3 ms 732 KB Output is correct
5 Correct 3 ms 732 KB Output is correct
6 Correct 2 ms 732 KB Output is correct
7 Correct 3 ms 732 KB Output is correct
8 Correct 3 ms 732 KB Output is correct
9 Correct 3 ms 732 KB Output is correct
10 Correct 2 ms 732 KB Output is correct
11 Correct 3 ms 732 KB Output is correct
12 Correct 45 ms 2412 KB Output is correct
13 Correct 337 ms 13796 KB Output is correct
14 Correct 143 ms 13796 KB Output is correct
15 Correct 186 ms 13796 KB Output is correct
16 Correct 64 ms 13796 KB Output is correct
17 Correct 164 ms 13796 KB Output is correct
18 Correct 166 ms 13796 KB Output is correct
19 Correct 279 ms 13796 KB Output is correct
20 Correct 57 ms 13796 KB Output is correct
21 Correct 180 ms 13832 KB Output is correct

Subtask #3
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 13832 KB Output is correct
2 Correct 2 ms 13832 KB Output is correct
3 Correct 2 ms 13832 KB Output is correct
4 Runtime error 3 ms 13832 KB Execution killed with signal 11 (could be triggered by violating memory limits)
5 Halted 0 ms 0 KB -

Subtask #4
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 13832 KB Output is correct
2 Correct 2 ms 13832 KB Output is correct
3 Correct 2 ms 13832 KB Output is correct
4 Runtime error 2 ms 13832 KB Execution killed with signal 11 (could be triggered by violating memory limits)
5 Halted 0 ms 0 KB -

Subtask #5
0 / 37.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 13832 KB Output is correct
2 Correct 2 ms 13832 KB Output is correct
3 Correct 2 ms 13832 KB Output is correct
4 Runtime error 2 ms 13832 KB Execution killed with signal 11 (could be triggered by violating memory limits)
5 Halted 0 ms 0 KB -