# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
45326 | imaxblue | 새로운 문제 (POI13_mor) | C++17 | 2645 ms | 65536 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define mp make_pair
#define pb push_back
#define x first
#define y second
#define pii pair<int, int>
#define p3i pair<pii, int>
#define pll pair<ll, ll>
#define p3l pair<pll, ll>
#define vi vector<int>
#define vpii vector<pii>
#define vp3i vector<p3i>
#define vpll vector<pll>
#define vp3l vector<p3l>
#define lseg L, (L+R)/2, N*2+1
#define rseg (L+R)/2+1, R, N*2+2
#define ub upper_bound
#define lb lower_bound
#define PQ priority_queue
#define MN 1000000007
#define fox(k, x) for (int k=0; k<x; ++k)
#define fox1(k, x) for (int k=1; k<=x; ++k)
#define foxr(k, x) for (int k=x-1; k>=0; --k)
#define fox1r(k, x) for (int k=x; k>0; --k)
#define ms multiset
#define flood(x) memset(x, 0x3f3f3f3f, sizeof x)
#define drain(x) memset(x, 0, sizeof x)
#define rng() ((rand() << 14)+rand())
#define scan(X) do{while((X=getchar())<'0'); for(X-='0'; '0'<=(_=getchar()); X=(X<<3)+(X<<1)+_-'0');}while(0)
char _;
#define pi 3.14159265358979323846
#define top front
int d[2][5005];
int n, m, q, x, y, w, N, D, p;
bool T, ans[1000005];
bitset<5005> u[2];
vector<int> v[5005];
vector<p3i> qn[5005];
queue<pair<int, int> > pq;
void dijk(int S){
flood(d); drain(u);
pq.push(mp(0, S));
while(!pq.empty()){
D=pq.top().x; T=D%2; N=pq.top().y; pq.pop();
if (u[T][N]) continue;
d[T][N]=D; u[T][N]=1;
fox(l, v[N].size()){
if (!u[!T][v[N][l]])
pq.push(mp(D+1, v[N][l]));
}
}
fox(l, qn[S].size()){
y=qn[S][l].x.x; w=qn[S][l].x.y; p=qn[S][l].y;
if (u[w%2][y] && v[y].size()==0) continue;
if (u[w%2][y] && d[w%2][y]<=w){
ans[p]=1;
}
}
}
int32_t main(){
scanf("%i%i%i", &n, &m, &q);
fox(l, m){
scanf("%i%i", &x, &y);
v[x].pb(y);
v[y].pb(x);
}
fox(l, q){
scanf("%i%i%i", &x, &y, &w);
qn[x].pb(mp(mp(y, w), l));
continue;
}
fox1(l, n){
dijk(l);
}
fox(l, q){
printf((ans[l]?"TAK\n":"NIE\n"));
}
return 0;
}
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