이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<vi> vvi;
typedef vector<vll> vvll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<pii> vpii;
typedef vector<pll> vpll;
typedef vector<vpii> vvpii;
typedef vector<vpll> vvpll;
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(x) (int)(x).size()
#define fi first
#define se second
template<class T> bool ckmin(T &a, const T &b) {return a > b ? a = b, 1 : 0;}
template<class T> bool ckmax(T &a, const T &b) {return a < b ? a = b, 1 : 0;}
namespace debug {
void __print(int x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(const char *x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}
template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for(auto z : x) cerr << (f++ ? "," : ""), __print(z); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if(sizeof...(v)) cerr << ", "; _print(v...);}
#ifdef ljuba
#define dbg(x...) cerr << "\e[91m" << "LINE(" << __LINE__ << ") -> " << "[" << #x << "] = ["; _print(x)
#else
#define dbg(x...)
#endif
}
using namespace debug;
const char nl = '\n';
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());
/*
погледај сампле тестове, пре него што имплементираш (можда имаш погрешну идеју)
уместо да разматраш неке глупе случајеве на папиру, размишљај заправо о задатку
*/
void solve() {
int n, x;
cin >> n >> x;
vi v(n);
for(auto &z : v)
cin >> z;
vi odg(n);
vi dp;
for(int i = 0; i < n; ++i) {
auto it = lower_bound(all(dp), v[i]+x);
if(it == dp.end()) {
odg[i] = sz(dp) + 1;
} else {
int pos = it - dp.begin();
odg[i] = pos + 1;
}
it = upper_bound(all(dp), v[i]);
if(it == dp.end()) {
dp.pb(v[i]);
} else {
*it = v[i];
}
}
//dbg(odg);
int ans = 0;
dp.clear();
vi suf;
for(int i = n-1; ~i; --i) {
auto it = lower_bound(all(dp), -v[i]);
int res = odg[i];
suf.pb(it-dp.begin());
res += (it - dp.begin());
ckmax(ans, res);
it = upper_bound(all(dp), -v[i]);
if(it == dp.end()) {
dp.pb(-v[i]);
} else {
*it = -v[i];
}
}
reverse(all(suf));
//dbg(suf);
cout << ans << nl;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int testCases = 1;
//cin >> testCases;
while(testCases--)
solve();
}
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