이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef vector<pair<long long, long long>> vii;
#define pb push_back
#define all(x) x.begin(), x.end()
const int V = 1e6 + 7;
const int N = 1e5 + 7;
const int S = 2e3 + 7;
const int inf = 1e9;
long long s, n, v[N], w[N], k[N];
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
#ifndef ONLINE_JUDGE
// freopen("test.inp", "r", stdin);
//freopen("test.out", "w", stdout);
#endif
cin >> s >> n;
for (int i = 1; i <= n; i++) cin >> v[i] >> w[i] >> k[i];
int mx = *max_element(k, k + n);
// Subtask 1
if (n == 1) {
cout << v[1] * min(s / w[1], k[1]) << endl;
}
// Subtask 2 & 3: Normal knapsack
else if (1 <= n && n <= 100 && mx <= 10) {
long long dp[2001];
memset(dp, 0, sizeof dp);
for (int i = 1; i <= n; i++)
for (int j = s; j >= w[i]; j--)
for (int t = 0; t <= k[i]; t++)
if (j >= w[i] * t) {
dp[j] = max(dp[j], dp[j - w[i] * t] + v[i] * t);
}
cout << dp[s] << endl;
}
// Subtask 4 & 5: knapsack with observation
else if (1 <= n && n <= 1e5 && mx <= 1e9) {
/*
Observation: The numbers of taken product must less than S since 1 <= Wi <= S -> maximum taken product: S / W[i]
-> consider the top valued S/W[i] items for each W[i]
*/
vii obj[S];
long long dp[2001];
memset(dp, 0, sizeof dp);
for (int i = 1; i <= n; i++) {
obj[w[i]].pb({v[i], k[i]});
}
for (int i = 0; i <= s; i++) {
if (obj[i].size() == 0) continue;
sort(all(obj[i]), greater<pair<int, int>>());
int id = 0;
for (int j = 0; j * i < s; j++) {
if (id >= obj[i].size()) break;
for (int k = s; k >= i; k--) {
dp[k] = max(dp[k], dp[k - i] + obj[i][id].first);
}
--obj[i][id].second;
if (obj[i][id].second == 0) ++id;
}
}
cout << dp[s] << endl;
}
}
컴파일 시 표준 에러 (stderr) 메시지
knapsack.cpp: In function 'int main()':
knapsack.cpp:66:16: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::pair<long long int, long long int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
66 | if (id >= obj[i].size()) break;
| ~~~^~~~~~~~~~~~~~~~
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