이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
#pragma optimize ("g",on)
#pragma GCC optimize ("Ofast")
#pragma GCC optimize ("unroll-loops")
#pragma GCC optimize ("03")
#pragma GCC target ("sse,sse2,sse3,ssse3,sse4,popcnt,abm,avx2,mmx,fma,avx,tune=native")
using namespace std;
#define all(a) a.begin(), a.end()
#define ll long long
#define pb push_back
#define nl '\n'
#define popb pop_back()
#define sz size()
#define ld long double
#define ull unsigned long long
#define F first
#define S second
#define fix fixed << setprecision
#define pii pair<int, int>
#define E exit (0)
#define int long long
const ll inf = (1ll << 62ll), N = 5e5 + 5, mod = 1e9 + 7;
signed main() {
	//freopen("invtrans.in", "r", stdin);
	//freopen("invtrans.out", "w", stdout);
	ios_base::sync_with_stdio(NULL);
	cin.tie(NULL);
	int n;
	cin >> n;
	int a[n + 1], b[n + 1];
	int dp[n + 1];
	dp[0] = 0;
	for (int i = 1; i <= n; i++) cin >> a[i];
	for (int i = 1; i <= n; i++) cin >> b[i];
	for (int i = 1; i <= n; i++) {
		dp[i] = 0;
		map<int, int> cnt;
		int mx = 0;
		for (int j = i; j >= 1; j--) {
			mx = max(mx, a[j]);
			cnt[b[j]]++;
			dp[i] = max(dp[i], dp[j - 1] + cnt[mx]);	
		}
	}
	cout << dp[n];
}	
컴파일 시 표준 에러 (stderr) 메시지
exam.cpp:3: warning: ignoring '#pragma optimize ' [-Wunknown-pragmas]
    3 | #pragma optimize ("g",on)
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