Submission #445487

#	Time	Username	Problem	Language	Result	Execution time	Memory
445487		lohacho	Vim (BOI13_vim)	C++14	77.28 / 100	98 ms	80440 KiB

vim

#include <bits/stdc++.h>
#define int long long
#define umi(x, y) (x = min(x, y))
#define uma(x, y) (x = max(x, y))
using namespace std;

int dp[70004][12][12], ns[70004];

signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int n; cin >> n;
    string in; cin >> in;
    string s;
    vector<int> must;
    int cnt = 0, ans = 0;
    for(auto&i:in){
        if(i == 'e') ++cnt;
        else{
            s += i; must.push_back(!!cnt);
            ans += cnt * 2;
            cnt = 0;
        }
    }
    n = (int)s.size();
    for(int i = 0; i < 70004; ++i) for(int j = 0; j < 12; ++j) for(int k = 0; k < 12; ++k) dp[i][j][k] = ns[i] = (int)1e9;
    for(int i = 1; i <= 11; ++i) dp[1][i][0] = 0;
    for(int i = 1; i < n; ++i){
        for(int j = 1; j <= 11; ++j){
            for(int k = 0; k <= 11; ++k){
                umi(dp[i][j][k], ns[i]);
                if(!k){
                    if(!must[i]){
                        umi(dp[i + 1][j][0], dp[i][j][0] + (s[i] - 'a' + 1 == j) * 2);
                    }
                    if(s[i] - 'a' + 1 == j){
                        umi(ns[i + 1], dp[i][j][k] + 2);
                    }
                    for(int x = 1; x <= 11; ++x){
                       umi(dp[i + 1][j][x], dp[i][j][0] + 1 + (s[i] - 'a' + 1 == j) * 2);
                    }
                }
                else{
                    if(s[i] - 'a' + 1 == j && j == k){
                        umi(ns[i + 1], dp[i][j][k] + 4);
                    }
                    else if(s[i] - 'a' + 1 == j){
                        umi(dp[i + 1][k][0], dp[i][j][k] + 2);
                        for(int x = 1; x <= 11; ++x){
                           umi(dp[i + 1][x][k], dp[i][j][k] + 3);
                        }
                    }
                    else if(s[i] - 'a' + 1 == k){
                        for(int x = 1; x <= 11; ++x){
                           umi(dp[i + 1][j][x], dp[i][j][k] + 3);
                        }
                    }
                    umi(dp[i + 1][j][k], dp[i][j][k] + 1 + (s[i] - 'a' + 1 == j) * 2 + (s[i] - 'a' + 1 == k) * 2);
                }
            }
        }
    }
    int ans2 = (int)1e9;
    for(int i = n - 1; i >= 0; --i){
        umi(ans2, dp[i][s[i] - 'a' + 1][11] + 2);
        if(must[i]) break;
    }
    cout << ans + ans2;
    return 0;
}

• Subtask 1: 40.27777777777778 / 50
• Subtask 2: 7 / 10
• Subtask 3: 30 / 40