이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// aww geometria !! :)
#include <bits/stdc++.h>
typedef long double ld;
using namespace std;
const ld eps = 1e-6;
ld maxr(ld x1, ld r1, ld x2, ld r2)
{
ld lo = 0., hi = r2;
while (abs(lo - hi) > eps)
{
ld mi = (lo + hi) / 2.;
ld xdif = x2-x1, ydif = abs(r1 - mi);
ld prepona = sqrt(xdif*xdif+ydif*ydif);
if (prepona < r1 + mi) // jeden az dva priesecnik, mozeme ist nizsie
hi = mi;
else lo = mi;
}
return (lo + hi) / 2.;
}
bool eq(ld x, ld y) { return abs(x - y) < eps; }
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout << fixed << setprecision(3);
int n;
cin >> n;
vector<ld> x(n), r(n);
vector<int> st;
for (int i = 0; i < n; i++)
{
cin >> x[i] >> r[i];
while (st.size() > 1 && maxr(x[st.back()], r[st.back()], x[i], r[i]) > maxr(x[st[st.size() - 2]], r[st[st.size() - 2]], x[i], r[i]))
st.pop_back();
if (!st.empty()) r[i] = min(r[i], maxr(x[st.back()], r[st.back()], x[i], r[i]));
st.push_back(i);
}
for (int i = 0; i < n; i++) cout << r[i] << "\n";
return 0;
}
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