제출 #442754

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
442754		SorahISA	던전 (IOI21_dungeons)	C++17	37 / 100	7120 ms	1125180 KiB

dungeons

#include "dungeons.h"
#pragma GCC optimize("Ofast", "unroll-loops")
#include <bits/stdc++.h>
using namespace std;

#define int long long
// #define double long double
using pii = pair<int, int>;
template<typename T>
using Prior = std::priority_queue<T>;
template<typename T>
using prior = std::priority_queue<T, vector<T>, greater<T>>;

#define X first
#define Y second
#define eb emplace_back
#define pb pop_back
#define pf pop_front
#define ALL(x) begin(x), end(x)
#define RALL(x) rbegin(x), rend(x)

namespace {

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

const int maxn = 4E5 + 5;
// const int maxn = 5E4 + 5;
const int lgmx = 24 + 1;
const int INF = 1E13;

int N;
vector<int> S, P, W, L;

int sum[lgmx/4+1][lgmx][maxn];
int32_t anc[lgmx/4+1][lgmx][maxn], mnm[lgmx/4+1][lgmx][maxn];

} /// end of namespace

void init(int32_t _N, vector<int32_t> _S, vector<int32_t> _P, vector<int32_t> _W, vector<int32_t> _L) {
    N = _N;
    for (auto &x : _S) S.eb(x);
    for (auto &x : _P) P.eb(x);
    for (auto &x : _W) W.eb(x);
    for (auto &x : _L) L.eb(x);
    S.eb(0), P.eb(0), W.eb(N), L.eb(N);
    
    memset(anc, 0x00, sizeof(anc));
    memset(sum, 0x00, sizeof(sum));
    memset(mnm, 0x00, sizeof(mnm));
    
    for (int lvl = 0; lvl <= lgmx/4; ++lvl) {
        
        /**
         * Assume strength is in [2^{4*lvl-4}, 2^{4*lvl}), every opponent with strength
         * greater or equal to 2^{4*lvl} is ignored and you lose immediately as we
         * only consider opponents with strength less than 2^{4*lvl} in this level.
        **/
        
        for (int i = 0; i <= N; ++i) {
            anc[lvl][0][i] = S[i] < (1<<(4*lvl)) ? W[i] : L[i];
            sum[lvl][0][i] = S[i] < (1<<(4*lvl)) ? S[i] : P[i];
            mnm[lvl][0][i] = S[i] < (1<<(4*lvl)) ? INF  : S[i];
        }
        
        for (int lay = 1; lay < lgmx; ++lay) {
            for (int i = 0; i <= N; ++i) {
                int32_t par = anc[lvl][lay-1][i];
                anc[lvl][lay][i] = anc[lvl][lay-1][par];
                sum[lvl][lay][i] = sum[lvl][lay-1][i] + sum[lvl][lay-1][par];
                int32_t tmp = mnm[lvl][lay-1][par];
                if (tmp != INF) tmp -= sum[lvl][lay-1][i];
                mnm[lvl][lay][i] = min(mnm[lvl][lay-1][i], max(0, tmp));
            }
        }
        
    }
}

int simulate(int32_t now, int32_t _Z) {
    int Z = _Z;
    while (now != N) {
        int lvl = __lg(Z) / 4;
        for (int lay = lgmx-1; lay >= 0; --lay) {
            if (Z < mnm[lvl][lay][now]) {
                Z += sum[lvl][lay][now];
                now = anc[lvl][lay][now];
            }
        }
        // cerr << "lvl = " << lvl << ", Z = " << Z << ", now = " << now << "\n";
        if (Z >= S[now]) Z += S[now], now = W[now];
        else             Z += P[now], now = L[now];
        // cerr << "lvl = " << lvl << ", Z = " << Z << ", now = " << now << "\n";
    }
    return Z;
}

• Subtask 1: 11 / 11
• Subtask 2: 26 / 26
• Subtask 3: 0 / 13
• Subtask 4: 0 / 12
• Subtask 5: 0 / 27
• Subtask 6: 0 / 11